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Usimov [2.4K]
3 years ago
15

A local meteorologist reports the days weather. Which information is qualitative? Check all that apply.

Chemistry
1 answer:
Leokris [45]3 years ago
3 0
A meterologist studies weather

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HELP Consider this equation...
Mashcka [7]

Answer:

it is not correct I have an answer for ''why''

Explanation:

You need to balance it

s= 2

0=2

S+30•2 --------> SO•3

2 2 2 2

S +3O•2-------->SO•2......MULTIPLY

2 4 2 4......LCM IS 4

2 1 2 1....DIVIDE BY 4

SO NOW WE GOT THE BALANCE NO. WE CAN PUT IT IN THE EQUATIONS.

2S+3O•2 -----> 2SO•3

now you can check the both sides its balances the correct answer is this

4 0
3 years ago
Read 2 more answers
Francine makes several measurements of the mass of a metal block. The data set is shown in the table below.
BARSIC [14]

Answer:

Mean

Explanation:

The mean of a series of measurements is calculated when a<em>ll the measurements are added up and then divided by the number of measurements taken</em>, as follows:

  • Sum of Measurements = 20.73 + 20.76 + 20.68 + 20.75 = 82.92

As<u> there are 4 measurements</u>, the mean is:

  • Mean = 82.92 / 4 = 20.73
3 0
3 years ago
Calculate the molarity of a salt solution with a volume of 0.250L that contains 0.70 mol of NaCl. (SHOW WORK)
Kazeer [188]

Answer:

= 0.28M

Explanation:

data:

volume = 0.250 L

           = 0.250dm^3                       ( 1litre = 1dm^3)

moles = 0.70 moles

Solution:

      molarity = \frac{no. of moles}{volume in dm^3}

                 = 0.70 / 0.250

    molarity = 0.28 M

5 0
2 years ago
An aluminum kettle weights 1.05 kg and has a heat capacity of 0.9211 J over grams Celsius how much heat is required to increase
Serggg [28]

Answer:

64799.4 J

Explanation:

The following data were obtained from the question:

Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g

Specific heat capacity (C) = 0.9211 J/g°C

Initial temperature (T1) = 23°C

Final temperature (T2) = 90°C

Change in temperature (ΔT) = T2 – T1 =

90°C – 23°C = 67°C

Heat required (Q) =....?

The heat required to increase the temperature of the kettle can b obtain as follow:

Q = MCΔT

Q = 1050 x 0.9211 x 67

Q = 64799.4 J

Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.

4 0
3 years ago
2. When multiplying or dividing measured numbers, we use the measurement with the least number of
Goryan [66]

Answer:

a. 105

b. 76.4

c. 0.04

d. 4.000

Explanation:

Question a. has three significant figures

Question b. has three significant figures

Question c. has one significant digit (only the 3 is significant in the question, zeros are only significant if they are trailing with the presence of a decimal point or in between two non-zero numbers)

Question d. has four significant figures

4 0
3 years ago
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