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2 years ago

Li2x what is the charge of x.

1 answer:

5 0

Ionic compounds are composed of an ion pair of opposite charge. Usually, the positive ion is a metal cation while the negative ion is a non metal anion. The two ions are held together by strong electrostatic interaction.

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Is aloe vera a living or non-living thing?

Afina-wow [57]

Answer:

It is a living plant

Explanation:

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3 years ago

What is 1520 9600 mg to kilograms

Ostrovityanka [42]

I Think that the answer is 15.2096 Kilograms, but I might be wrong.

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3 years ago

A chemist determined by measurements that 0.030 moles of barium participated in a chemical reaction. Calculate the mass of bariu

schepotkina [342]

Answer: 4.1 g of barium precipitated.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}$

Given : moles of barium = 0.030

Molar mass of barium = 137 g/mol

$0.030=\frac{x}{137}$

x= 4.1 g

Thus there are 4.1 g of barium that precipitated.

3 0

3 years ago

To which group of alcohols does 3,4-dimethyl-2-pentanol belong?

dsp73

Answer:

The answer is A

Explanation:

8 0

2 years ago

If is found that 24.68 mL of .1165 M NaOH is needed to titrate .2931 g of an unknown acid to the phenolphthalein end point. Calc

Lemur [1.5K]

Answer: The equivalent mass of the acid is 83.16 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$

Molarity of $NaOH$ solution = 0.1165 M

Volume of $NaOH$ solution = 24.68 mL = 0.02468 L

Putting values in equation 1, we get:

$\text{Moles of} NaOH={0.1165M}\times{0.02468L}=2.875\times 10^{-3}moles=2.875\times 10^{-3}geq$

( as acidity of NaOH is 1)

For end point: gram equivalents of acid = gram equivalents of base = $2.875\times 10^{-3}$

Mass of acid= $gram equivalents\times {\text {Equivalent mass}}$

$0.2391=2.875\times 10^{-3}\times {\text {Equivalent mass}}$

${\text {Equivalent mass}}=83.16g$

Thus equivalent mass of the acid is 83.16 grams

5 0

3 years ago