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natima [27]
3 years ago
5

How do take off my question when I don't have a question?

Chemistry
2 answers:
kotegsom [21]3 years ago
7 0
Why would you ask a question if you didnt have a question?

Just get someone to report it, and itll be deleted
Liono4ka [1.6K]3 years ago
3 0
I think you just have to live through the misery of having a question u already know the answer to <span />
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When an acid and a base are mixed together, a neutralization reaction occurs. the products of an acid-base reaction do not have
Cloud [144]

This is generally true, though if either the acid or base (or both) is a weak base, the reaction may not go to completion and the properties of the mixture may be more complicated.

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3 years ago
An aluminum sample has a mass of 80.01 g and a density of 2.70 g/cm3. According to the data, to what number of significant figur
notsponge [240]
Not 100% sure, but I'd have to say this:

When rounding for sig figs, you look at the other numbers in your calculation and see which one has the least amount of sig figs. This number is 2.70. (3 sig figs). So, you round to 3 significant figures in your calculation.

Hope this helped!
6 0
3 years ago
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What is the unit of Avogadro's number?
kompoz [17]

Answer:

it may be electron, atom or ions depend on the nature of the substance and the character of reaction

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3 years ago
What makes a theory a good theory
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sientific method creating scientific theory

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sience brob

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3 years ago
The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr
jenyasd209 [6]

Answer : The final temperature of the water is, 22.5166^oC

Explanation : Given,

Mass of benzene = 8.600 g

Molar mass of benzene = 78 g/mole

First we have to calculate the moles of benzene.

\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole

Now we have to calculate the energy of combustion.

The given balanced chemical reaction is:

2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ

According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives \frac{6542 kJ}{2}\times 0.1103=360.7913kJ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})

where,

q_w = heat released = 360.7913 kJ = 36079.13 J

m_w = mass of water = 5691 g

c_w = specific heat of water= 4.18J/g^oC

T_{final} = final temperature = ?

T_{initial} = initial temperature = 21^oC

Now put all the given values in the above formula, we get:

36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)

T_{final}=22.5166^oC

Therefore, the final temperature of the water is, 22.5166^oC

8 0
4 years ago
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