The reaction given is:
4Ga + P4 ---> 4GaP
The oxidation number of the reactants is zero, because they are pure elements.
The P in compounds may have oxidation states 3- or 5-. Gallium may only have oxidation state 3+.
Then, to be neutral in GaP the oxidation states are 3+ for Ga and 3- for P.
And the transference of electrons can be see in this oxidation - reduction equations:
Ga (0) - 3 e- ----> Ga (3+)
P (0) + 3e- ---> P (3-)
So, for one formula unit, 3 electrons have been transfered from each Ga atom to P atom to form one GaP unit.
Answer: 3 electrons.
Answer:
The following three isomeric structure are given below.
Explanation:
Structure of the following three isomeric esters with chemical formula C₇H₁₂O₂
Ester #1: methyl 1-methylcyclobutanecarboxylate
Ester #2: (E)-methyl 3-methyl-3-pentenoate
Ester #3: isopropyl 2-methylpropenoate
Answer:
yes solution is always a mixture but not all mixtures are solution
Explanation:
A solution.is a homogeneous mixture of substance that have uniform composition throughout
And a mixture hVe twoo or more substances that are not chemically.combine
Explanation:
Normally, fusion involves two heavy hydrogen nuclides but since we have 4 light hydrogen nuclides, two of which underwent positron emission, thus changing two protons into neutrons plus 2 positrons and 2 neutrinos. The resulting nucleus from this fusion reaction is an He-4 nucleus.
Answer:
Explanation:
Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.
Metal X can form 2 oxides (A and B).
A + B = 3g
The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.
The mass of metal X in the two oxides will be the same because it's the same metal.
Thus, we represent the mass of the metal in the two oxides as 2X.
2X + 0.72 + 1.16 = 3
2X + 1.88 = 3
2X = 3 - 1.88
2X = 1.12
X = 0.56
<u>Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.</u>
Thus, mass of metal (X) in 1g of oxygen in A is
0.56g ⇒ 0.72g
X ⇒ 1
X = 1 × 0.56/0.72
X = 0.78 g
Hence, 0.78g of the metal will combine with 1g of oxygen for A
Also, mass of metal (X) in 1g of oxygen in B is
0.56g ⇒ 1.16g
X ⇒ 1g
X = 1×0.56/1.16
X = 0.48 g
Thus, 0.48g of the metal will combine with 1g of oxygen for B