The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
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Answer:
500 pounds
Step-by-step explanation:
Let the pressure applied to the leverage bar be represented by p
Let the distance from the object be represented by d.
The pressure applied to a leverage bar varies inversely as the distance from the object.
Written mathematically, we have:
Introducing the constant of proportionality
If 150 pounds is required for a distance of 10 inches from the object
Therefore, the relationship between p and d is:
When d=3 Inches
The pressure applied when the distance is 3 inches is 500 pounds.
That it is that many deviations away from the mean.
M to the power 4 squared minus 23
4x (-2s+4x^2)
is an multiplication expression
