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RoseWind [281]
3 years ago
6

12 = -3x - 21 What does x equal to?

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
5 0

Answer:

x is equal to -11.

Step-by-step explanation:

This is because you isolate x, and solve.

jonny [76]3 years ago
5 0
X=-11 bc math stuff

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Please help quickly !!
Alisiya [41]

Answer:

answer is 26000000

Step-by-step explanation:

10+14/7×-8=26

26 × 1000000=26000000

plz follow and like and make brainliest answer

4 0
3 years ago
0.3 x 103<br>0 3 x 1025<br>Write the following as an ordinary number. [<br>(1 Point<br>3x10​
Ne4ueva [31]
0.3 x 103 = 30.9
0.3 x 1025 = 307.5

3 x 10^5 = 300,000
3 0
2 years ago
Can some help please?!?!
Alexandra [31]

Answer:

<em>Choice D.</em>

Step-by-step explanation:

Vertical line test for functions:

If a vertical line drawn anywhere on the graph intersects the graph in more than one point, it is not a function.

If you draw a vertical line passing through any point between x = -4 and x = 4, the line will intersect two points on the circle. The relation fails the vertical line test. That shows that this relation is not a function.

6 0
3 years ago
A painter is going to paint the rooms of a building. The painter has used 80 gallons of paint and has painted 32% of the rooms.
timurjin [86]

Answer:

30 gallons

Step-by-step explanation:

4 0
2 years ago
Researchers have discovered a new genetic marker for a form of cancer. Twelve percent of the overall population carry this marke
In-s [12.5K]

Answer:

The probability that a person with the marker develops cancer is 0.0725.

Step-by-step explanation:

Let's denote the events as follows:

<em>A</em> = a person has cancer

<em>B</em> = a person carries the marker.

<u>Given:</u>

P (A) = 0.03

P (B) = 0.12

P (B|A) = 0.29

The conditional probability of an event <em>X</em> provided that another event <em>Y</em> has already occurred is:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y)}

Use the conditional probability formula to compute the probability that a person with the marker develops cancer.

P(A|B)=\frac{P(B|A)P(A)}{P(B)} =\frac{0.29\times0.03}{0.12}=0.0725

Thus, the probability that a person with the marker develops cancer is 0.0725.

3 0
3 years ago
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