Answer:
The points are: (16.12,0),(-8.12,0).
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:



Distance between two points:
Suppose we have two points,
and
. The distance between them is given by:

Find all points on the x-axis that are 14 units from the point (4, -7).
Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).
The distance is 14. So






So 



The points are: (16.12,0),(-8.12,0).
We are looking at points in the form (x, y).
Let x = pounds of red grapes
Let y = pounds of green grapes
Audrey has less than 5 pounds of grapes. Here is where I think you made a typo. The question should indicate if Audrey has 5 pounds less of red grapes or green grapes.
Go back and check your original problem and then come back.
plug a=2 and b=4 in the expression
5(2)+7(4)
simplify
10+28
solve
=38
True, a diameter is an example
Answer:
<em>Respuesta: B</em>
Step-by-step explanation:
<u>Patrones de secuencia</u>
Consiste en una serie de elementos conectados entre sí por una regla fija, de tipo numérica, lógica o de razonamiento.
La primera figura de la imagen muestra un rectángulo con un círculo sin rellenar dentro. La segunda figura muestra dos cambios claramente visibles:
* La figura externa ahora es interna y viceversa.
* La figura interna estaba sin relleno y ahora lo tiene
La tercera figura muestra una cruz con un círculo sin rellenar dentro. Si aplicamos la misma regla, la siguiente figura debería tener:
* Una cruz dentro de un círculo
* La cruz debe estar rellena
Sólo la figura B cumple con estas condiciones.
Respuesta: B