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sineoko [7]
3 years ago
6

Una función impar con quien tiene simetría?

Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0
Para que algo sea una función impar, debe tener simetría con el origen, no con el eje x. Esto significa que si tiene un punto como (a, b) también tiene los puntos (-a, -b). Por ejemplo, y = x es una función extraña porque hace esto.

Las funciones pueden ser simétricas sobre el eje y, lo que significa que si reflejamos su gráfica sobre el eje y obtendremos la misma gráfica. Hay otras funciones que podemos reflejar tanto en el eje x como en el eje y y obtener la misma gráfica. Estos son dos tipos de simetría que llamamos funciones pares e impares.
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What number is the height changing by each minute
Sveta_85 [38]

The height is changing by 0.5 each minute

<h3>How to determine the number?</h3>

The question implies that we calculate the slope of the table

From the table of values, we have the following points

(0, 150) and (1, 150.5)

The slope is then calculated as:

m = (y2 - y1)/(x2 -x1)

This gives

m = (150.5 - 150)/(1 - 0)

Evaluate

m = 0.5

Hence, the height is changing by 0.5 each minute

Read more about slope at:

brainly.com/question/3493733

#SPJ1

8 0
2 years ago
The amount of warpage in a type of wafer used in the manufacture of integrated circuits has mean 1.3 mm and standard deviation 0
valina [46]

Answer:

a) P(\bar X >1.305)=P(Z>\frac{1.305-1.3}{\frac{0.1}{\sqrt{200}}}=0.707)

And using the complement rule, a calculator, excel or the normal standard table we have that:

P(Z>0.707)=1-P(Z

b) z=-0.674

And if we solve for a we got

a=1.3 -0.674* \frac{0.1}{\sqrt{200}}=

So the value of height that separates the bottom 95% of data from the top 5% is 1.295.

c) P( \bar X >1.305) = 0.05  

We can use the z score formula:

P( \bar X >1.305) = 1-P(\bar X

Then we have this:

P(z< \frac{1.305-1.3}{\frac{0.1}{\sqrt{n}}}) = 0.95

And a value that accumulates 0.95 of the area on the normal distribution z = 1.64 and we can solve for n like this:

n = (1.64*\frac{0.1}{1.305-1.3})^2= 1075.84 \approx 1076

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

Let X the random variable that represent the amount of warpage of a population and we know

Where \mu=1.3 and \sigma=0.1

Since the sample size is large enough we can use the central limit theorem andwe know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

P(\bar X >1.305)=P(Z>\frac{1.305-1.3}{\frac{0.1}{\sqrt{200}}}=0.707)

And using the complement rule, a calculator, excel or the normal standard table we have that:

P(Z>0.707)=1-P(Z

Part b

For this part we want to find a value a, such that we satisfy this condition:

P(\bar X>a)=0.75   (a)

P(\bar X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for a we got

a=1.3 -0.674* \frac{0.1}{\sqrt{200}}=

So the value of height that separates the bottom 95% of data from the top 5% is 1.295.

Part c

For this case we want this condition:

P( \bar X >1.305) = 0.05  

We can use the z score formula:

P( \bar X >1.305) = 1-P(\bar X

Then we have this:

P(z< \frac{1.305-1.3}{\frac{0.1}{\sqrt{n}}}) = 0.95

And a value that accumulates 0.95 of the area on the normal distribution z = 1.64 and we can solve for n like this:

n = (1.64*\frac{0.1}{1.305-1.3})^2= 1075.84 \approx 1076

6 0
3 years ago
The probability that Rahul succeeds at any given free-throw is 70%, percent. He was curious how many free-throws he can expect t
True [87]

Answer:

Step-by-step explanation:is 13/20=0.65

8 0
3 years ago
Use the calculator to graph the functions y = -x + 5 + 2 and y=-(x - 1)2 + 3. Which statement is true?
Nitella [24]
The y is greater than the function
5 0
3 years ago
I need help with his question
Doss [256]

Answer:

27-24i

Step-by-step explanation:

It is trust me:)

3 0
3 years ago
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