Question

A body to projected horizontally with a velocity of 100m/s

Answer 1

Answer:

(a) Time flight is 6.39 s

(b) The range of the projectile is 639 m.

Explanation:

Given;

initial horizontal velocity of the projectile, $v_x$ = 100 m/s

initial vertical velocity of the projectile, $v_y$ = 0

height of the tower, h = 200 m

(a) Time flight is calculated as follows;

$h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 200}{9.8} }\\\\t = 6.39 \ s$

(b) The range of the projectile is calculated as follows;

$R = v_x \times t\\\\R = 100\ m/s \ \times \ 6.39\ s\\\\R = 639 \ m$