Answer:
The lever is a movable bar that pivots on a fulcrum attached to a fixed point. The lever operates by applying forces at different distances from the fulcrum, or a pivot. As the lever rotates around the fulcrum, points farther from this pivot move faster than points closer to the pivot.
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The acceleration of the car,
Here, v is final velocity, u is initial velocity and t is time taken by the car.
Given , and
Therefore, from above equation
.
Here, negative sign shows deceleration of a car.
Thus the the magnitude of car acceleration is .
Answer:
Option C. Rate of change of velocity
Explanation:
To know the correct answer to the question, it is important we know the definition of power.
Power can be defined as the rate at which work is done. Mathematically, it is expressed as:
Power = work / time
Work and energy has the same unit of measurement i.e joule. Thus, power can also be defined as the rate at which energy is transferred i.e
Power = enery / time
Energy is measured in Joules and time in second. Thus, power can also be defined as amount of joules transfered per second.
Power = Joule / sec
The rate of change of velocity on the other hand is termed acceleration.
Thus, the answer to the question is option C.
Answer:
Ffriction = 90 N
coefficient = 0.3
Explanation:
First, note that the sum of all the forces in the x directions equals the mass multiplied by the acceleration in the x direction.
assuming the direction of the pulling force is positive,
243 N - Ffriction = m * a
m= 30.6 kg
a= 5 m/s/s
Ffriction= 243 - m*a
Ffriction= 243 - (30.6)(5)
Ffriction=90 N
The force of friction is equal to the coefficient of friction multiplied by the normal force on the object. Because the pulling force is completely horizontal, the normal force of the object is equal to its weight, which is m * g, or (30.6 kg)(9.8 m/s/s) = 299.88 N
Ffriction = coefficient * Fnormal
90 = coefficient * 299.88
coefficient = 0.3