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3 years ago

What do you mean by resistance of conductor?state it’s unit.

Physics

1 answer:

dalvyx [7]3 years ago

7 0

Answer:

its unit is Ohm

Explanation:

Resistance means material which resist the passing current through it and the value of resistance says how much the material is resisting the current and it temperature dependent and the unit is Ohm.

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Se necesita subir una carga de 500 kg (4900 N) a una altura de 1.5 m deslizándola sobre una rampa inclinada. ¿Qué longitud debe

marusya05 [52]

Answer:

4.22 m

Explanation:

Una rampa es una máquina que se utiliza para levantar un objeto con una fuerza menor a la que realmente necesitarías. Cuanto mayor sea la longitud de la rampa, menor será la magnitud de la fuerza necesaria para levantar el objeto.

Dado que:

altura de la rampa = 1.5 m, carga = 4900 N, fuerza aplicada = 1633.33 N.

La fórmula de la rampa se da como:

fuerza aplicada * longitud de la rampa = peso de la carga * altura de la rampa

1633.33 * longitud de la rampa = 4900 * 1.5

longitud de la rampa = 4900 * 1.5 / 1633.33

longitud de la rampa = 4.22 m

6 0

3 years ago

A 3 N force pushes on a object for 20 meters. Find the work done

astraxan [27]

W = Fx

w = 3.20 = 60 N.m

6 0

3 years ago

A metal object with a mass of 19g is heated to 96c, then transferred to a calorimeter containg 75g of water at 18c. the water an

avanturin [10]

Let us say that Cp is the specific heat of the metal object. Then we do a heat balance (heat lost by metal = heat gained by water):

- 19g * Cp * (22degC – 96degC) = 75g * 4.184J/g degC * (22degC – 18degC)

6 0

3 years ago

Read 2 more answers

a vector a has components a x equals -5.00 m in a y equals 9.00 meters find the magnitude and the direction of the vector

Murrr4er [49]

Answer:

The magnitude = 10.30 m

The direction of the vector proceeds at angle of 119.05°

Explanation:

Given that:

A vector $\bar A$ has component $A_x$ = -5 m and $A_y$ = 9 m

The magnitude of vector $\bar A$ can be represented as:

$\bar A$ = $\sqrt{A_x^2 + A_y^2}$

$\bar A$ = $\sqrt{(-5)^2 + (9)^2}$

$\bar A$ = $\sqrt{25 + 81}$

$\bar A$ = $\sqrt{106}$

$\bar A$ = 10.30 m

If we make $\bar A$ an angle $\theta$ with y- axis:

Then; tan $\theta$ = $\frac{A_x}{A_y}$

tan $\theta$ = $\frac{5}{9}$

tan $\theta$ = 0.555

$\theta$ = tan⁻¹ (0.555)

$\theta$ = 29.05°

Angle with positive x-axis = 90 + $\theta$

= 90° + 29.05°

= 119.05°

5 0

3 years ago

Three parallel wires each carry current I in the directions shown in (Figure 1). The separation between adjacent wires is d.

jasenka [17]

(a) The magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

(b) The magnitude of the net magnetic force per unit length on the middle wire is zero.

<h3>Force per unit length</h3>

The magnitude of the net magnetic force per unit length on the top wire is calculated as follows;

F₁/L = (μI₁/2π) x (I₂/d + I₃/d)

F₁/L = (μI/2π) x (I/d + I/d)

F₁/L = (μI/2π) x (2I/d)

F₁/L = μI²/πd

The magnitude of the net magnetic force per unit length on the middle wire is calculated as follows;

F₂/L = (μI₂/2π) x (I₃/d - I₁/d)

F₂/L = (μI/2π) x (I/d - I/d) = 0

The magnitude of the net magnetic force per unit length on the middle bottom is calculated as follows;

F₃/L = (μI₂/2π) x (I₁/d + I₂/d)

F₃/L = (μI/2π) x (I/2d + I/d)

F₃/L = (μI/2π) x (3I/2d)

F₃/L = 3μI²/4πd

Thus, the magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

The magnitude of the net magnetic force per unit length on the middle wire is zero.

The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

Learn more about magnetic force here: brainly.com/question/13277365

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6 0

2 years ago