In an atom of hydrogen the orbit radius is given by the formula:
r = n² · α₀
where:
n = number of orbit = 15
α₀ = Bohr radius (innermost radius) = 0.529 Â
Since d = 2 · r, we can write:
d = n² · d₀
= 15² · 1.06
= 238.5 Â
Hence, the <span>diameter of the fifteenth orbit of the hydrogen atom is 238.5 </span>Â.
Answer:
60000 N
Explanation:
Neglecting air resistance,
Using equation Net force = mass x acceleration (F=ma),
F = 12000 x 5
F = 60000 N
Answer:
corona, chromosphere, radiative zone, convection zone,core
The <span>actinides and lanthanides.</span>
Answer:
Lower pitch and longer wavelength
Explanation: