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NikAS [45]
3 years ago
12

A guy wire connects the top of a 18 3/4 foot tall tornado siren to the ground where Samson's shadow ends. The distance from the

base of the siren pole to where the wire touches the ground is 120 feet. If Samson is 6 1/4 feet tall and his head barely touches the guy wire where he is standing, how long is Samson's shadow?
Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

40 feet

Step-by-step explanation:

Required:

Find the length of Samson's shadow

The question can be illustrated with the attached figure where Samson's shadow is represented with x.

To solve for x, we make use of the following equivalent ratios:

18.75 : 120 = 6.25 : x

Convert to fraction

\frac{18.75}{120} = \frac{6.25}{x}

Cross Multiply

18.75 * x = 120 * 6.25

18.75 * x = 750

Make x the subject

x =\frac{750}{18.75}

x =40

<em>Hence, Samson's shadow is 40ft</em>

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Factor the expression 20k+50 explain every step you did
slamgirl [31]
So, to factorise something you are taking out the highest common factor.Here, 10 is an example of the highest common factor (I’ll refer to this as HCF)

10(2k+5)

Everything inside the brakets is multiplied by what’s directly next to it (if there is a negative sign, then that is included). So, 10 x 2k = 20k and 10 x 5 = 50

10(2k + 5) is the factorised version of 20k + 50
4 0
3 years ago
The sum of 2, 6, and a number amounts to 15. Find the number.
ikadub [295]
Given the numbers, let’s set up an equation:

2 + 6 + n = 15

We can solve this using steps:

1. Simplify

8 + n = 15

2. Subtract 8 from both sides

(8 - 8) + n = 15 - 8

3. Simplify

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Let’s plug in 7 to see if it makes sense:

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Our unknown number is 7.
8 0
1 year ago
1. (a) Let A = 1, 3, 5, 7 and B = X : X is the first three multiple of 7 . Find (A−B).
ICE Princess25 [194]

Answer:

a) A-B = { 1 , 3, 5 }

b) The remainder is 50

c) f + g)(x) = x⁴+ 5x³

d) \frac{dy}{dx} = \frac{2x- y^3(3x^2))     }{ 1- x^3 3y^2}

Step-by-step explanation:

Step(I):-

1) a)

Let A = { 1, 3, 5, 7 } and B = { 7 , 14 , 21 }

A - B = {1,3,5,7} - { 7,14,21}

A - B  = { 1 , 3, 5}

b)

Given f (x)=3x³−11x−48

    x-1  ) 3 x³ - 11x -48 (- 3x²-3x -2

            -3<u>x³ +3x</u>²

                 3x²-11x-48

                <u> -3x²+9x</u>

<u> </u>                      2x -48

                    -2x +2  

                    <u>                     </u>

                         50

The remainder is 50

   

c)  Given f(x) = x³ and g(x) = x + 5

(f. g)(x) = f(x) .g(x) = x³ . (x+5) = x³(x) + 5 x³ = x⁴+ 5x³

d)

 Given function   y = 3 + x²+x³y³  ...(I)

By using derivative formulas

            y = xⁿ

            \frac{dy}{dx} = n x^{n-1}

Apply d/dx ( UV) = U V¹ + V U¹



Differentiating equation (I) with respective to 'x' , we get

                      \frac{dy}{dx} = 0 + 2x + ( x^3 3y^2(\frac{dy}{dx} )+ y^3(3x^2))

                     \frac{dy}{dx} - ( x^3 3y^2(\frac{dy}{dx} )= 2x- y^3(3x^2))

                   \frac{dy}{dx} = \frac{2x- y^3(3x^2))     }{ 1- x^3 3y^2}



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Answer:

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Step-by-step explanation:

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