The answer is 2, 4, 8 and 16 (added=$30)
Take $14 from the highest amount = $2 for that envelope
Double the original $2 = $4
Double the $4 = $8
Double the $6 = $16
Thus, $2,4,8,16, but all in different envelopes
A. would be y=4x-14
B. would be y=4x+11
C. would be y=x/4 - 11/4
D. would be y=x/4 + 7/2
Hope this helps! :)
I believe the answer is the second answer
The denominator would still be the same you placed the marble back into the bag
Answer:
b = 6 sqrt(2)
Step-by-step explanation:
Since this is right triangle, we can use the Pythagorean theorem
a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse
3^2 + b^2 = 9^2
9+b^2 = 81
b^2 = 81-9
b^2 = 72
Take the square root of each side
sqrt(b^2) = sqrt(72)
b = sqrt(36*2)
b = 6 sqrt(2)
