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3 years ago

PLEASE HELP ME!!!!!! IM LOW ON POINTS BUT I NEED SOME HELP, QUICK!!! POINTS FOR HELPFUL ANSWERS + BRAINLIEST!!!!!

Engineering

1 answer:

meriva3 years ago

8 0

Answer:

Kitchen sinks can be clogged for a few reasons, food hair, and other things. Overtime, buildup of these things lead to clogging.

A few methods to fix clogging are, baking soda mixture, plunging, and boiling water.

The first method, baking soda mixture, what you do is you pour a cup of baking soda and vinegar down the drain, and place a rubber stopper to cover the drain opening. Wait 10 or more minutes, and take out the stopper, and run hot tap water until it's unclogged.

The second method is plunging. Make sure the sink has enough water to submerge the plunger, and start plunging. While you are plunging, maintain a good seal to get the best results. This usually works, but sometimes it doesn't.

The last method is boiling water. Pour boiling water into the drain, then after a while, the clogged drain should unclog, if it doesn't repeat the process until necessary.

Explanation:

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Evaluate each of the following to three significant figures and express each answer in SI units using an appropriate prefix: (a)

Sonbull [250]

Answer:

Explanation:

(a)

$\frac{354 mg \, 45 km}{0.0356 kN} = 354 mg \times \frac{1 kg}{10^6 mg} \times 45 km \times \frac{10^3m}{1 km} \times \frac{1}{0.0356 kN} \times \frac{1 kN}{10^3 N} = 0.447 \frac{kg \, m}{N}$

(b)

$0.00453 Mg \times 201 ms = 0.00453 Mg \times \frac{10^3 kg}{1 Mg} \times 201 ms \times \frac{1 s}{10^3 ms} = 0.911 kg \, s$

(c)

$\frac{435 MN}{23.2 mm} = 435 MN \times \frac{10^6 N}{1 MN} \times \frac{1}{23.2 mm} \times \frac{10^3 mm}{1 m} = 18.75 \times 10^9 \frac{N}{m} = 18.75 \frac{GN}{m}$

7 0

4 years ago

When storing used oil, it needs to be kept in ___________ containers. A) MetalB) PlasticC) UncoveredD) Leakproof

Romashka-Z-Leto [24]

Answer:

D. Leak-proof

Explanation:

Used oils are required to be stored in closed containers or tanks which will remain closed when oil is not added or removed. Alternatively, used oils can be stored in containers labeled "Used Oil" for regulated hazardous waste storing. A leak-proof container is one that has no drips and dribbles when the container lid is closed. These containers should be kept in good conditions away from rusting, leaks or deteriorations. It is important to mention that used oil should not be stored in anything apart from tanks and leak-proof storage containers.

8 0

3 years ago

External crack of length of 3.0 mm was detected on the surface of the shaft of wind turbine made from 4340 steel. The diameter o

sveticcg [70]

Answer:

The correct answer is " $K_c=6.0369 \ MPa\sqrt{m}$ ".

Explanation:

Given:

Maximum load,

P = 50,000 N

Crack length,

a = 3mm

or,

= 3×10⁻³ m

Diameter,

d = 32 mm

As we know,

⇒ Maximum stress, $\sigma=\frac{P}{A}$

$=\frac{50000}{(\frac{\pi}{4}\times 32^2)}$

$=62.20 \ N/mm^2$

Now,

⇒ Fracture tougness, $K_c=Y \sigma\sqrt{\pi a}$

On substituting the values, we get

$=1\times 62.20\times \sqrt{3.14\times 3\times 10^{-3}}$

$=6.0369 \ MPa\sqrt{m}$

4 0

3 years ago

Which is/are not a mechanism commonly associated with tool wear (mark all that apply)?a. Adhesion b. Attrition c. Abrasion d. Co

butalik [34]

Answer: d)Coercion

Explanation:Tool wear is defined as the situation when the cutting tool is subjected to the regular process of cutting metal then they tend to wear because of the continuous action of cutting and facing stresses and pressure . The mechanism that does not happen during this process are coercion that means the process of exerting forces on any material forcefully against the will or need. Therefore, adhesion,attrition and abrasion are the process of tool wear .So the correct option is (d)

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3 years ago

What are two factors that determine the thermal energy of a substance

Sav [38]

Mass and chemical composition

6 0

3 years ago