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Valentin [98]
3 years ago
12

When storing used oil, it needs to be kept in ___________ containers. A) MetalB) PlasticC) UncoveredD) Leakproof

Engineering
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

D. Leak-proof

Explanation:

Used oils are required to be stored in closed containers or tanks which will remain closed when oil is not added or removed. Alternatively, used oils can be stored in containers labeled "Used Oil"  for regulated hazardous waste storing. A leak-proof container is one that has no drips and dribbles when the container lid is closed. These containers should be kept in good conditions away from rusting, leaks or deteriorations. It is important to mention that used oil should not be stored in anything apart from tanks and leak-proof storage containers.

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A classroom which normally contains 26 people is to be air- conditioned. A person in the classroom typically dissipates heat at
lutik1710 [3]

Answer:

Explanation:

Heat dissipated by 26 people per second

= 26 x 360 x 1000 / (60 x 60)

= 2600 J

Heat dissipated by bulbs per second

= 15 x 40

= 600 J

Heat dissipated by fans per second

200 J

Heat dissipated by air coming in

= 200 x 10 x 1000 / (60 x 60)

=555.55 J

Heat gain by walls

= 5000 x 1000 / (60 x 60)

= 1388.88 J

Total heat gain per second

= 2600 + 600+200+555.55

= 3955.55 J

Capacity of air-conditioner required

= 3955.55 J/s

= 3.9 kJ/s

= 3.9kW

= 4 kW

7 0
3 years ago
Create a program, using at least one For Loop, that displays the Sales Amounts in each of 4 regions during a period of three mon
kari74 [83]

Answer:

C++ code explained below

Explanation:

/*C++ program that prompts sales for four regions of three sales and prints

the sales values to console */

#include<iostream>

#include<iomanip>

#include<cstring>

using namespace std;

int main()

{

  //set constant values

  const int SALES=3;

  const int REGIONS=4;

  //create an array of four regions

  string regionNames[]={"Region 1","Region 2","Region 3","Region 4"};

  //create a 2D array to read sales

  int sales[REGIONS][SALES];

  //read sales for four regions

  for(int region=0;region<REGIONS;region++)

  {

      cout<<regionNames[region]<<endl;

      for(int sale=0;sale<SALES;sale++)

      {

          cout<<"Enter sales ";

          cin>>sales[region][sale];

      }

  }

  //print sales

  for(int region=0;region<REGIONS;region++)

  {

      cout<<regionNames[region]<<"-";

      for(int sale=0;sale<SALES;sale++)

      {

          cout<<setw(5)<<sales[region][sale];

      }

      cout<<endl;

  }

  //pause program output on console

  system("pause");

  return 0;

}

5 0
4 years ago
A very specific part of the population is called a
V125BC [204]
A specific part of the population is a subgroup.
6 0
3 years ago
If you have a hole diameter of 0.250 with a tolerance of ±0.005, what are the limits of the hole size?
sleet_krkn [62]

Answer:

The limits of the hole size are;

The maximum limit of the hole diameter 0.255

The minimum limit of the hole diameter = 0.245

Explanation:

Tolerance is a standardized form of language that can be used to define the intended 'tightness' or 'clearance' degree between mating parts in a mechanical assembly process and in metal joining processes such as welding and brazing processes

In tolerancing, the size used in the description of a part is known as the nominal size while allowable variation of the nominal size that will still allow the part to function properly is known as the tolerance

A tolerance given in the form ±P is known as bilateral tolerancing, with the value being added to or subtracted from the nominal size to get the maximum and minimum allowable limits of the dimensions of the nominal size

Therefore;

The given nominal dimension of the hole diameter = 0.250

The bilateral tolerance of the dimension, = ±0.005

Therefore;

The maximum limit of the diameter of the hole = 0.250 + 0.005 = 0.255

The minimum limit of the diameter of the hole = 0.250 - 0.005 = 0.245

7 0
3 years ago
After reading through the code, what will happen when you click run?* 1 point when run move forward while there is a pile do rem
KATRIN_1 [288]

Explanation:

I'm not exactly a master at coding, but I'm pretty sure that:

The farmer will remove dirt as long as there is a pile, then stop when the pile is done.

5 0
3 years ago
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