Answer:
The answer is "
"
Explanation:
Please find the complete question in the attached file.
Its change in temperature in pipes depends on rate heads and loss in pipes owing to pipe flow, contractual loss, etc.
The temperature change thus relies on V1 v2 p d D L.
Answer:
Option A
Question (in proper order)
What is the correct expression of the internal moment in segment AB? A 10-ft-long cantilever beam is fixed at end A (x = 0). A uniform distributed load of 2 kip/ft is applied between A and B (x = 6 ft). A downward 10-kip force is applied at B, and an upward 8-kip force is applied at end C (x = 10 ft). In addition, a clockwise couple moment of 40 kip-ft is exerted at the free end C. What is the correct expression of the internal moment in segment AB?
<em>(First Diagram attached below)</em>
Explanation:
(From the second diagram attached below)
Note that
<em>Moment of a force is the product of the force and the perpendicular distance</em>
<em>sum of horizontal forces, ∑Fx = 0 (that is sum of forces acting towards left = sum of forces acting towards right)</em>
that is zero in this case
<em>Sum of vertical forces, ∑Fy = 0 ( that is sum of forces acting upward = sum of forces acting downward)</em>
Total upward force = Total downward force
Ay + 8 = 10 + 2 x 6
where Ay is the force acting at the fixed end
Ay + 8 = 10 + 12
Ay = 22 - 8
Ay = 14 Kip ( force is measured in kip while distance is measured in ft)
<em>Sum of clockwise moment = Sum of anticlockwise moment</em>
let us assume a counterclockwise moment about point A = Ma
8 x 10 + Ma = 40(counterclockwise moment) + (2 x 6) x 3(total uniform force assumed to act at the middle of the 6ft length) + 10 x 6
80 + Ma = 40 + 36 + 60
Ma = 136 - 80
Ma = 56 kip-fit
(From the third diagram attached below)
Consider a section of beam AB from A to X and of distance x fit
let the counterclockwise moment about Xx section be Mx
if we take moment about the Xx section
then
summation of moment about the Xx section ∑Mxx = 0
hence,
Mx + 56 + {(2 * x)[<em>total of the uniform force</em>] * x/2[<em>acting at the middle point of the x ft distance</em>]} = Ay * x
Mx + 56 + 2x * x/2 = 14 * x
Mx + 56 + x^2 = 14x
Mx = kip-ft
