Its B
rise over run dictates that its 2/8 which simplifies to 1/4
and its at an upward angle from left to right therefore its positive.
Answer:
it would be 90 degrees clocwise
Answer:
(i) 15 m, 6 m/s
(ii) 90 m
Step-by-step explanation:
(i) For some acceleration (a) from rest, the distance covered (d) in time t is ...
d = (1/2)at^2
The distance covered by Ben in the 5 seconds he is accelerating is ...
d = (1/2)(1.2 m/s²)(5 s)² = 15 m
Of course, Ben's speed at that point is ...
s = (1.2 m/s²)(5 s) = 6 m/s
__
(ii) When Ben has been walking 5 s, Alan has been walking 10 s, so Alan has covered (10 s)(4 m/s) = 40 m. Their distance difference of 40 -15 = 25 m is being made up at the rate of their speed differences: (6 m/s) -(4 m/s) = 2 m/s.
It will take (25 m)/(2 m/s) = 12.5 s additional time for Ben to catch Alan. In the 22.5 s that Alan has been walking before they meet, he will have walked ...
(22.5 s)(4 m/s) = 90 m . . . the distance OP
the solutions to the related equation are 0,2,3 .
<u>Step-by-step explanation:</u>
Here we have , function f(x) = x3 – 5x2 + 6x . Graph of this function is given below . We need to find What are the solutions to the related equation . Let's find out:
Solution of graph means the value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !
At x = 0 .
From the graph , at x=0 we have f(x) = 0 i.e.
⇒ ![f(x) = x^3- 5x^2 + 6x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E3-%205x%5E2%20%2B%206x)
⇒ ![f(0) = 0^3- 5(0)^2 + 6(0)](https://tex.z-dn.net/?f=f%280%29%20%3D%200%5E3-%205%280%29%5E2%20%2B%206%280%29)
⇒ ![f(0) =0](https://tex.z-dn.net/?f=f%280%29%20%3D0)
At x = 2 .
From the graph , at x=2 we have f(x) = 0 i.e.
⇒ ![f(x) = x^3- 5x^2 + 6x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E3-%205x%5E2%20%2B%206x)
⇒ ![f(0) = 2^3- 5(2)^2 + 6(2)](https://tex.z-dn.net/?f=f%280%29%20%3D%202%5E3-%205%282%29%5E2%20%2B%206%282%29)
⇒ ![f(0) =0](https://tex.z-dn.net/?f=f%280%29%20%3D0)
At x=3 .
From the graph , at x=3 we have f(x) = 0 i.e.
⇒ ![f(x) = x^3- 5x^2 + 6x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E3-%205x%5E2%20%2B%206x)
⇒ ![f(0) = 3^3- 5(3)^2 + 6(3)](https://tex.z-dn.net/?f=f%280%29%20%3D%203%5E3-%205%283%29%5E2%20%2B%206%283%29)
⇒ ![f(0) =0](https://tex.z-dn.net/?f=f%280%29%20%3D0)
Therefore , the solutions to the related equation are 0,2,3 .
Answer: ![170^{\circ}](https://tex.z-dn.net/?f=170%5E%7B%5Ccirc%7D)
Step-by-step explanation:
Given
The dog has a 25 ft leash
Arc length is 74.3 ft
Arc length is given by
![l=\dfrac{\theta }{360^{\circ}}\times 2\pi r](https://tex.z-dn.net/?f=l%3D%5Cdfrac%7B%5Ctheta%20%7D%7B360%5E%7B%5Ccirc%7D%7D%5Ctimes%202%5Cpi%20r)
here, r=25 ft
l=74.3 ft
Put the values
![\Rightarrow 74.3=\dfrac{\theta }{360^{\circ}}\times 2\pi \times 25\\\\\Rightarrow \theta =170.2^{\circ} \approx 170^{\circ}](https://tex.z-dn.net/?f=%5CRightarrow%2074.3%3D%5Cdfrac%7B%5Ctheta%20%7D%7B360%5E%7B%5Ccirc%7D%7D%5Ctimes%202%5Cpi%20%5Ctimes%2025%5C%5C%5C%5C%5CRightarrow%20%5Ctheta%20%3D170.2%5E%7B%5Ccirc%7D%20%5Capprox%20170%5E%7B%5Ccirc%7D)
The measure of the angle is ![170^{\circ}](https://tex.z-dn.net/?f=170%5E%7B%5Ccirc%7D)