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3 years ago

Write the steps you would use to solve the following quadratic equation (X+3)²=6. Show two different methods.

Mathematics

1 answer:

Aliun [14]3 years ago

6 0

X^2+6x+9 that is one method

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What is the distance between (-5, 5) and (1, -2)

Murrr4er [49]

Answer:

$\displaystyle d=\sqrt{85}\text{, or about 9.22 units}$

Step-by-step explanation:

We will use the distance formula to solve.

$\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}$

$\displaystyle d=\sqrt{(1--5)^2 +(-2-5)^2}$

$\displaystyle d=\sqrt{(6)^2 +(-7)^2}$

$\displaystyle d=\sqrt{36+49}$

$\displaystyle d=\sqrt{85}\text{, or about 9.22 units}$

Read more about using the distance formula here: brainly.com/question/15691280

6 0

11 months ago

Graph the function f(x)=3/2x−4. Use the line tool and select two points to graph.

iris [78.8K]

Answer:

Two points on the graph would be (2,-1) and (4,2).

Step-by-step explanation:

You can choose two random x variables such as how i selected 2 and 4. if you change the variable x to those values you can solve for y or in this case f(x).

EX:

3/2*2-4

6/2-4

3-4

f(x)= -1

4 0

2 years ago

Read 2 more answers

What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?

Daniel [21]

Our angle teta is:
teta = 3pi/4

since that is larger than pi/2 but less than pi that means that our angle lies in II quadrant (x negative y positive)

sin(3pi/4) = √2/2
cosine and tangent of that angle must be negative because of position of the angle.

cos(3pi/4) = -√2/2
tan(3pi/4) = -1

7 0

3 years ago

Let x^2+18x=44 . What values make an equivalent number sentence after completing the square?

Lostsunrise [7]

To find the final term to compete the square you need to divide the 'x' term by 2 then square it

$x^2 +18x + = 44+ \\ x^2+18x+( \frac{18}{2} )^2=44+( \frac{18}{2} )^2 \\ x^2+18x+9^2=44+9^2 \\ x^2+18x+81=44+81 \\ (x+9)^2=125$ - equivalent equation

6 0

3 years ago

Read 2 more answers

The LCM of two numbers is 60. Their GCf is 6 and their difference is 18. What are the two numbers?

Aliun [14]

$LCM(x,y)=60\\
GCF(x,y)=6\\
x-y=18\\\\
LCM(x,y)=\dfrac{|x\cdot y|}{GCD(x,y)}\\
60=\dfrac{|x\cdot y|}{6}\\
|x\cdot y|=360\\\\\\
|x\cdot y|=360\\
x-y=18\\\\
|x\cdot y|=360\\
x=18+y\\\\
|(18+y)\cdot y|=360\\
|18y+y^2|=360\\
18y+y^2=360 \vee 18y+y^2=-360\\
y^2+18y+81=441 \vee y^2+18y+81=-279\\
(y+9)^2=441 \vee (y+9)^2=-279\\
y+9=\sqrt{441} \vee y+9=-\sqrt{441}\\
y=21-9 \vee y=-21-9\\
y=12 \vee y=-30\\\\
x-12=18 \vee x-(-30)=18\\
x=30 \vee x=-12\\\\
\boxed{x=30, y=12 \vee x=-12, y=-30}$

4 0

3 years ago

Read 2 more answers