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loris [4]
3 years ago
11

How do you do 5a) and 5b)????? Please help!!!!

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
5 0

Answer:

31° F and 67° F

Step-by-step explanation:

(a)

When t = 0 then

f(0) = 31 + \frac{0}{100} = 31 + 0 = 31° F

(b)

When t = 10 , then

f(10) = 31 + \frac{40(10^3)}{10^3+100} = 31 + \frac{40000}{1100} = 31 + 36.36... ≈ 67° F

Ray Of Light [21]3 years ago
3 0

Answer:

21.0 { { {1221220 =  223jn}^{n \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \tan( \beta  \beta  \beta  \beta  \beta  \beta \pi\pi) } }^{2} }^{2}  \times \frac{?}{?}

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2. Determine if either of the following equations are functions? Draw the graphs and explain how
nekit [7.7K]

Answer:

Both equation represent functions

Step-by-step explanation:

The function is the relation that for each input, there is only one output.

A. Consider the equation

y=-\dfrac{3}{5}x+2

This equation represents the function, because for each input value x, there is exactly one output value y.

To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.

When you intersect the graph of the function y=-\dfrac{3}{5}x+2 with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.

B. Consider the equation

y=x-x^2

This equation represents the function, because for each input value x, there is exactly one output value y.

When you intersect the graph of the function y=x-x^2 with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.

4 0
3 years ago
An article titled "Teen Boys Forget Whatever It Was" appeared in the Australian newspaper The Mercury (April 21, 1997). It descr
Step2247 [10]

Answer:

We conclude that the average attention span for teenage boys is less than 5 minutes.

Step-by-step explanation:

We are given that the mean time to distraction for teenage boys working on an independent task was 4 minutes.

Suppose that this mean was based on a random sample of 50 teenage Australian boys and that the sample standard deviation was 1.4 minutes.

<u><em>Let </em></u>\mu<u><em> = average attention span for teenage boys</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 5 minutes    {means that the average attention span for teenage boys is more than or equal to 5 minutes}

Alternate Hypothesis, H_A : \mu < 5 minutes    {means that the average attention span for teenage boys is less than 5 minutes}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                    T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean attention time span for teenage boys = 4 min

             s = sample standard deviation = 1.4 min

             n = sample of teenage boys = 50

So, <u><em>the test statistics</em></u>  =  \frac{4-5}{\frac{1.4}{\sqrt{50} } }  ~  t_4_9

                                     =  -5.051

Now at 0.01 significance level, the t table gives critical value of -2.405 at 49 degree of freedom for left-tailed test. Since our test statistics is less than the critical value of t as -2.405 > -5.051, <u>so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</u>

Therefore, we conclude that the average attention span for teenage boys is less than 5 minutes.

8 0
4 years ago
Items 2-4. Points P, Q, and Sare
Ivanshal [37]

Answer:

See below

Step-by-step explanation:

2......................

∠PQR and ∠RQS are supplementary, which add up 180°

  • ∠PQR = 3x - 5
  • ∠RQS = x + 1

<u>Sum:</u>

  • 3x - 5 + x + 1 = 180
  • 4x - 4 = 180
  • 4x = 184
  • x = 46°

3......................

  • ∠PQR = 3x - 5 = 3*46° - 5° = 138° - 5° = 133°

4......................

From the picture and the value of x we got above:

  • ∠RQS = x + 1 = 46 + 1= 47°

QT bisects ∠RQS and we get two equal angles

<u>Each will measure:</u>

  • 47°/2 = 23.5°

5......................

LM = 5, LN = 17, MN = ?

<u>If L is between M and N, then</u>

  • MN = LM + LN = 5 + 17 = 22

<u>M is between L and N, then</u>

  • MN = LN - LM = 17 - 5 = 12

5......................

<u>Ray BD bisects ∠ABC, then formed angles are equal:</u>

  • m∠DBC = x + 6
  • m∠ABD = 2x - 12

m∠DBC = m∠ABD

  • x + 6 = 2x - 12
  • 2x - x =6 + 12
  • x = 18°

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4 years ago
Quien responda la operación se lleva 100 puntos en mi otra cuenta
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Answer:

I don't even know

Step-by-step explanation:

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7 0
3 years ago
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Find the equations for a helix that has a radius of 8, a height of 12 and does exactly two complete revolutions (starting at the
Slav-nsk [51]

By the equations according to the <em>cylindrical</em> system of coordinates, the equation for a helix are x = 8 · cos (2π · t /T), y = 8 · sin (2π · t /T) and z = 6 · (t/T).

<h3>How to derive the equations of a helix in cylindrical form</h3>

According to the <em>cylindrical</em> system of coordinates, helix can be described by the following equations:

Radius

x = r · cos (2π · t /T)     (1)

y = r · sin (2π · t /T)      (2)

Height

z = H · (t/T)     (3)

Where T is the period of one <em>complete</em> revolution.

If we know that r = 8 and H = 6, then the equations for the helix is:

x = 8 · cos (2π · t /T)

y = 8 · sin (2π · t /T)

z = 6 · (t/T)

How to learn more on helices: brainly.com/question/16911869

#SPJ1

6 0
2 years ago
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