2 years ago

PLEASE HELPPPPPP!!!!!!!!!!!!!!!

Mathematics

1 answer:

kotykmax [81]2 years ago

4 0

Answer:

a ) 2¹/2

Step-by-step explanation:

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Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than

liraira [26]

Given:

Atul has $\dfrac{2}{3}$ lb of candy.

Jose has $\dfrac{3}{5}$ lb of candy.

Maria has $\dfrac{1}{2}$ lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has $\dfrac{1}{2}$ lb less than Jose, therefore

Maria has = $\dfrac{3}{5}-\dfrac{1}{2}$ lb

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Difference between the candies Atul and Maria have.

Difference = $\dfrac{2}{3}-\dfrac{1}{10}$ lb

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Therefore, Atul have $\dfrac{17}{30}$ lb of candy more than Maria.

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