4 years ago

Why is the mileage a vehicle gets less when burning e85 than 100 percent gasoline?

Mathematics

1 answer:

Otrada [13]4 years ago

6 0

It has less ethanol

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Answer:

The UCL is $UCL = 0.054$

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Step-by-step explanation:

From the question we are told that

The quantity of each sample is n = 30

The average of defective products is $p = 0.025$

Now the upper control limit [UCL] is mathematically represented as

$UCL = p + 3 \sqrt{\frac{p(1-p)}{n} }$

substituting values

$UCL = 0.025 + 3 \sqrt{\frac{0.025 (1-0.025)}{30} }$

$UCL = 0.054$

The upper control limit (LCL) is mathematically represented as

$LCL = p - 3 \sqrt{\frac{p(1-p)}{n} }$

substituting values

$LCL = 0.025 - 3 \sqrt{\frac{0.025 (1-0.025)}{30} }$

$LCL = -0.004$

$LCL \approx 0$

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1198.08
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