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2 years ago

6 x 2 1/5 estimated please hurry

Mathematics

2 answers:

Lapatulllka [165]2 years ago

8 0

13.2 ......................

horrorfan [7]2 years ago

5 0

6 x 2 1/5 estimated is $\frac{6x^{22} }{5}$

~~Hope dis helpz u~~

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Zachary created a garden that measured7 x 6.5 feet. How many 8-foot rolls of fencing will he need to completely surround the gar

lutik1710 [3]

Answer:

6 rolls

Step-by-step explanation:

7 × 6.5 is 45.5

45.5 ÷ 8 is 5.6875

5.6875≈6

So 6!

8 0

3 years ago

The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can use as an estimator for p $\hat p =0.5$ . And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

3 0

3 years ago

What is the geometric mean of 2 and 25? Rounded to the nearest tenth

Drupady [299]

The geometric mean is $\sqrt{2*25} = \sqrt{50}= 5\sqrt{2}=7.1$ .

3 0

3 years ago

Beans begin to sprout on the 14th day. Consider the value predicted by the model on the 14th day. Which statement is true?

otez555 [7]

Answer:

Where are the statements? i can't help if none are provided

Step-by-step explanation:

8 0

3 years ago

In a group of 40 people, 35% have never been abroad. Two people are selected at random without replacement and are asked about t

Alisiya [41]

Answer:

$\frac{7}{60}$

Step-by-step explanation:

Given that in a group of 40 people, 35% have never been abroad. Two people are selected at random without replacement and are asked about their past travel experience.

Since the two are drawn without replacement the first trial affects the second trial. In other words, each trial is not independent of the other.

a) Hence this cannot be binomial experiment. The reason is p=probability for each trial is not constant as first draw affect the probability for Ii draw

b) The probability that in a random sample of 2, no one has been abroad

=Prob of selecting both people from the group where no one has been abroad

We have in the group 35% i.e. 14 people never been to abroad

So required probability = Prob of selecting both from 14 people

= $\frac{14C2}{40C2} \\=\frac{14*13}{40*39} \\=\frac{7}{60}$

3 0

3 years ago