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Sindrei [870]
3 years ago
7

What is the value of A and B find the square root of two times the square root of 14 equals a multiplied by the square root of B

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

What is the value of A and B find the square root of two times the square root of 14 equals a multiplied by the square root of BWhat is the value of A and B find the square root of two times the square root of 14 equals a multiplied by the square root of BB) x= -13/2

C) x=25/28

D) x=-7/20What is the value of A and B find the square root of two times the square root of 14 equals a multiplied by the square root of B14Which equation below compares the amount of medicine, S, in Sofia’s system with the amount of medicine, L, in Lexi’s system? L = 16 x S S = 16 x L L = 4 + S S = 4 + L16What is the value of A and B find the square root of two times the square root of 14 equals a multiplied by the square root of B14What is the value of A and B find the square root of two times the square root of 14 equals a multiplied by the square root of BB) x= -13/2

C) x=25/28

D) x=-7/20

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Solve the equation 9 = (3/8)y​
Scilla [17]

Hello! :)

\large\boxed{y = 24}

9 = (3/8)y

Solve for y.

Isolate y by dividing both sides by 3/8, or multiplying by its reciprocal (8/3)

9 · (8/3) = (3/8)y · (8/3)

72 / 3 = y

y = 24

3 0
2 years ago
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Digiron [165]

Answer:

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Step-by-step explanation:

6 0
3 years ago
A manufacturing plant uses light bulbs whose life spans are normally distributed, with mean and standard deviation equal to 500
meriva

Answer:

602.50 hours

Step-by-step explanation:

Given that a  manufacturing plant uses light bulbs whose life spans are normally distributed, with mean and standard deviation equal to 500 and 50 hours,

It was decided to replace the bulbs so that no more than 2% of the bulbs to burn out between replacement periods

i.e. we have to construct 98% confidence interval right tailed to get this.

Z value is 2.05 for this (Upper tailed 0.98 probability)

Hence margin of error = 2.05 (std dev)\\=2.05(50)\\= 102.50

The upper bound for this would be

500+102.50 =602.50

So to keep below 2% the bulbs to burn out it should be replaced before 602.50 hours.

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3 years ago
MATH HELP!!!!<br><br> 2(3x+7)
Andreyy89
2(3x+7)=6x+14 you're using the distributive property in this
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3 years ago
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