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Mrac [35]
3 years ago
7

Find the surface area of the following figures.with solution please. T-T​

Mathematics
1 answer:
VMariaS [17]3 years ago
6 0

Answer:

I will do 1 2 3 and 5 for you:

Since a cube has a given length of 5, we know that all sides will be the same therefore your lengths will be the same.

There are 6 sides of a cube so,

5 x 5 = 25 area of one flat surface.

Now 25(an area of one flat surface) x 6(flat surfaces) = 150 cm for question 1

We need to find area of the two circles:

3(given radius)^2(radius being squared) x 3.14(pi)

3 x 3 = 9

9(after radius being squared) x 3.14(pi) = 28.26(area of one circle)

28.26 x 2 = <em>56.52 </em>(area of 2 circles)

Now we need to find the round surface, but first we need to find circumference:

2 x 3.14 x 3 = 18.84

18.84(circumference) x 5(height) = <em>94.2</em> (area of round surface)

Now lets add all the given areas to find surface area:

56.52 + 94.2 = 150.72 cm^2 is your answer for question 2

2 x 4 = 8

8 x 2 = 16

4 x 5 = 20

20 x 2 = 40

2 x 5 = 10

10 x 2 = 20

Add all given areas:

16 + 40 + 20 = 76 cm^2 is your answer for question 3

452.16 cm^2

4 x 3.14 x 6^2

4 x 3.14 x 36 = 452.16 cm^2 is your answer for question 4

8 x 4 = 32, 32 divided by 2 = 16

since there are 4 sides,

4 x 16 = 64

Don't forget the bottom!

4x 4 = 16

Lets add the given areas:

64 + 16 = 80 for question 5

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Answer:

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Step-by-step explanation:

We want to find the equation of the parabola with a focus of (3,1) and directrix y=5.

Considering the directrix, the quadratic graph must open downwards.


The equation of this parabola is given by the formula,

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Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,


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The equation of the parabola now becomes,


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Also |p| is the distance between the vertex and the directrix.


|p|=2


This implies that p=-2\:or\:2.


Since the parabola turns downwards,


p=-2.



Our equation now becomes,


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(x-3)^2=-8(y-3).


We make y the subject to get,

y=-\frac{1}{8}(x-3)^2+3).


This is the same as

f(x)=-\frac{1}{8}(x-3)^2+3).









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