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Lerok [7]
3 years ago
5

You construct a voltaic cell for the following chemical reaction: Tl3+(aq) + 2Cr2+(aq) → Tl+(aq) + 2Cr3+(aq) The measured cell p

otential under standard conditions is +1.19 V. Given that E°red for Cr3+(aq) | Cr2+(aq) is -0.41 V, what is E°red for Tl3+(aq) | Tl+(aq)?
Chemistry
1 answer:
Dominik [7]3 years ago
3 0

Answer:

E°red for Tl³⁺(aq) | Tl⁺(aq) is 0.78 V

Explanation:

According to cell reaction we can predict which one cathode half cell and which one anode.

We know left hand side electrode where oxidation occur acts as an anode and right hand side electrode where reduction take place acts as an cathode.

Hence Cr²⁺ converted into Cr³⁺ since oxidation is take place where as Ti³⁺ converted into Ti⁺ means reduction take place.

<u>Anode half cell  </u>is         Cr³⁺(aq) | Cr²⁺(aq) is  E⁰red = -0.41 V

<u>Cathode half cell</u> is         Ti³⁺(aq) | Ti⁺(aq)  is  E⁰red = ?  

                 E⁰cell = E⁰cathode - E⁰anode

        ⇒     E⁰cathode = E⁰cell + E⁰anode

        ⇒     E⁰cathode = 1.19 + (- 0.41) volt = 0.78 V

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During experiments, there are errors made:

• uncertainty in measurements

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• losses during separation (e.g. filtration or purification)

• Some side reactions might also happen.



Among the given options, only conservation of mass does not contribute to a lower actual yield compared to the theoretical yield.

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The correct answer is "They can be separated by physical processes"

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In an experiment, 34.8243g of copper (II) nitrate hydrate, Cu(NO3)2•zH2O was heated to a constant mass of 27.0351g. Calculate th
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Answer:

1) The mass of water lost = 7.7892 grams

2) Z = 3: Cu(NO3)2*3H2O

Explanation:

<u>Step 1: </u>Data given

Mass of copper (II) nitrate hydrate, Cu(NO3)2•zH2O = 34.8243 grams

Mass of substance after heating = 27.0351 grams

Molar mass of Cu(NO3)2 = 187.56 g/mol

Molar mass of H2O = 18.02 g/mol

<u>Step 2:</u> Calculate mass of water

The mass of water is the mass lost after heating.

Mass water = 34.8243 - 27.0351 = 7.7892 grams of water

<u>Step 3:</u> Calculate moles of Cu(NO3)2

Moles Cu(NO3)2 = Mass Cu(NO3)2 / Molar mass Cu(NO3)2

Moles Cu(NO3)2 = 27.0351 grams / 187.56 g/mol

Moles Cu(NO3)2 = 0.144 moles

<u>Step 4:</u> Calculate moles of H2O

Moles H2O = 7.7892 grams / 18.02 g/mol

Moles H2O = 0.432 moles

<u>Step 5:</u> Calculate Z

z = moles H2O / moles Cu(NO3)2

Z = 0.432/0.144

Z = 3

This means we have 3 water molecules in the formula. This makes the formula ofthe hydrate: Cu(NO3)2*3H2O

5 0
3 years ago
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