Given:
Sulfur dioxide and dihydrogen sulfide system
Vapor Pressure of water, H2O = 23 torr
P_SO2 = P_H2S
Temperature of the system = 298 K
Assume: Total pressure of the system is 1 atm = 760 torr
If partial pressure of SO2 is equal to the concentration of H2S, then,
760 = 0.5*PSO2 + 0.5PH2S
760 = PSO2
Answer:
Age of the ancient wood object is 11460 years.
Explanation:
We know that half-life for carbon-14 is 5730 years. That means the activity of the sample will decrease to half every 5730 years.
Now we construct the following table:
activity (counts/min) age of the wooden object
40 0
20 5730
10 11460
47% yield.
First, let's determine how many moles of ethane was used and how many moles of CO2 produced. Start with the respective atomic weights.
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass C2H6 = 2 * 12.0107 + 6 * 1.00794 = 30.06904 g/mol
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 g/mol
Moles C2H6 = 8 g / 30.06904 g/mol = 0.266054387 mol
Moles CO2 = 11 g / 44.0087 g/mol = 0.249950578 mol
Looking at the balanced equation, for every 2 moles of C2H6 consumed, 4 moles of CO2 should be produced. So at 100% yield, we should have 0.266054387 / 2 * 4 = 0.532108774 moles of CO2. But we only have 0.249950578 moles, or 0.249950578 / 0.532108774 = 0.46973587 =
46.973587% of what was expected.
Rounding to 2 significant figures gives 47% yield.
Tap water and rain water are both homogeneous, even though they may have different levels of dissolved minerals and gases. A bottle of alcohol is a man-made homogeneous mixture, from a fine Italian wine to a glass of Scotch whisky. In the human body, blood plasma is an example of a homogeneous mixture.
N just use a electronegativity table
