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3 years ago

HELPPPPPPPPP………………….

Chemistry

2 answers:

grandymaker [24]3 years ago

8 0

In a Punnett square, lower case letters are recessive alleles and upper case letters are dominant alleles. So, "tt" would mean that both alleles are recessive. In comparison, "Tt" would mean that one allele is dominant and one is recessive. Therefore zero would be tall as their is no T trait from either parents.

Tatiana [17]3 years ago

3 0

Answer:

Explanation:

because when you are doing punnet squares you have two letters that represent something but in your case I'm guessing that t means a short plant and T means a tall plant. an you want to know what percent will be tall, but there are 4 quadrants or four quarters and four quarters = a dollar so 4 of these equals one hundred percent so each one is 25%. The reason why it is 0 is because you would do...(file one) and as you can see there is no Ts so the answer is 0.

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A solution is made by dissolving 100. g of cobalt(III)chloride in 250. g of water. to make a solution that has a density of 1.25

Mariulka [41]

Answer:

Option A) (I) 2.42 m (II) 2.16 M

Explanation:

Let's determine some information.

Solute = CoCl₃ (molar mass = 165.29 g/m); mass of 100 g

Solvent = Water, mass of 250 g

Solution mass = mass of CoCl₃ + mass of water

250 g + 100 g = 350 g of solution

If we want to reach molarity (mol/L), let's determine solution volume with density:

Solution density = solution mass / solution volume

1.25 g/mL = 350 g / solution volume

Solution volume = 350 g / 1.25 g/mL = 280 mL

Let's convert the volume to L → 280 mL = 0.280L

Let's convert the mass of solute to moles = 100 g / 165.29 g/m →0.605 mol

Mol/L = 0.605 moles / 0.280 L = 2.16 M

Now let's calculate molalilty (mol/kg of solvet)

We must convert solvent mass to kg → 250g = 0.250 kg

Then, 0.605 moles / 0.250 kg =2.42 m

8 0

4 years ago

As we climb a mountain to a higher altitude, we experience a pressure increase.(T/F)

kenny6666 [7]

Answer:

As we climb a mountain to a higher altitude, we experience a pressure increase. -True

3 0

3 years ago

Write the Lewis structure for the product that forms when boron trifluoride combines with ammonia. Remember to show all non-zero

horrorfan [7]

Answer:

To draw or sketch a Lewis structure, formula or diagram, the chemical formula of the compound is essential. Without it you can not even know what are the atoms that make it up, in our case it is the one observed in the reaction shown:

$BF_{3}$ + $:NH_{3}$ ⇒ F3 $F_{3} BNH_{3}$

In the structure obtained (see the Lewis structure in the drawing) the black dots correspond to the electrons of the non-shared pairs. Because hydrogen has a single electron and a single orbital available to fill, it forms only a covalent bond represented by a long dash. The same goes for boron and fluorine but in this case the fluorine has pairs of free electrons.

Explanation:

Lewis's structure is all that representation of covalent bonds within a molecule or an ion. In it, said bonds and electrons are represented by long dots or dashes, although most of the times the dots correspond to non-shared electrons and dashes to covalent bonds.

All existing compounds can be represented by Lewis structures, giving a first approximation of how the molecule or ions could be.

8 0

3 years ago

"what is the maximum number of moles of nickel carbonate"

Elza [17]

The maximum number of moles of Nickel Carbonate (NiCO₃) that can form during a precipitation reaction is 0.025 mol. Hope this helped and have a great day!

4 0

3 years ago

Read 2 more answers

Please please help me solve this, I have a test and only 20 mins left T-T<br>

Ann [662]

Answer: $5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.Explanation:The balanced chemical equation is:
[tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)$

According to stoichiometry :

2 moles of $NH_4NO_3$ produce = 4 moles of $NO_2$ gas and 1 mole of $O_2$ gas

2 moles of $NH_4NO_3$ produce = 5 moles of gas

Thus 0.1 mole of $NH_4NO_3$ produce = $\frac{5}{2}\times 0.1=0.25moles$ of gas

Volume of gas produced = $moles\times {\text {Molar volume}}=0.25moles\times 22.4dm^3/mol=5.6dm^3$

Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.

7 0

3 years ago