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Serjik [45]
3 years ago
10

En una estructura de concreto cuyo peso es de 8500 n se apoyo sobre un area de 25cm2,hallar la presion ejercida sobre su base

Chemistry
1 answer:
babymother [125]3 years ago
5 0

Respuesta:

340 N/cm²

Explicación:

Paso 1: Información provista

Peso de la estructura (F): 8500 Newton

Area superficial (A): 25 cm²

Paso 2: Calcular la presión (P) ejercida por la estructura de concreto sobre su base

La presión es igual al cociente entre la fuerza ejercida y la superficie sobre la que se aplica.

P = F/A

P = 8500 N / 25 cm² = 340 N/cm²

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<em></em>

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We can use two equations for this problem.<span>

t1/2 = ln 2 / λ = 0.693 / λ
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Nt = Nο eΛ(-λt)                (2)

Where Nt is atoms at t time, No is the initial amount of substance, λ is decay constant and t is the time taken.
t = 40 days</span>

<span>No = 200 g

From (1) and (2),
Nt =  200 g eΛ(-(0.693 / 20 days) 40 days)
<span>Nt = 50.01 g</span></span><span>

</span>Hence, 50.01 grams of isotope will remain after 40 days.

<span>
</span>

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