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BARSIC [14]
3 years ago
15

A balloon moves vertically upward at

Chemistry
1 answer:
Usimov [2.4K]3 years ago
6 0

Answer:

B. Velocity

Explanation:

The answer is Velocity because the def of velocity is the rate of constant speed in a given direction. I hope this helps, have a good night.

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A million one thousand

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What is one way to test whether an unknown solution is acidic or basic?
sertanlavr [38]

Answer: There are several ways. The first that comes to mind is a pH meter. A pH electrode Is lowered into the solution, and (Assuming) the pH Meter has been properly calibrated, and the temperature of the solution is set to the calibration of the Meter, the pH can be read directly from an analogue scale or digital readout. Below 7 is acidic, 7 is Neutral, (like Pure Water), and over 7 is Alkaline, or Basic.

A useful, but less accurate method is the use of any number of “pH Indicator Solutions”, which are essentially a type of various colored dyes that change color within differing pH ranges. Usually, if the pH is unknown, a small amount of solution is removed from the container and tested separately - in a “well plate”, or similar method.

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Mr X was accused of speeding along a highway. He was travelling at different speeds,but an average speed of 80 km/h. Based on th
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7 0
4 years ago
A 6.35 l sample of carbon monoxide is collected at 55.0◦c and 0.892 atm. What volume will the gas occupy at 1.05 atm and 59.0◦c?
Sonja [21]

Answer : The final volume of gas will be, 5.46 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.892 atm

P_2 = final pressure of gas = 1.05 atm

V_1 = initial volume of gas = 6.35 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 55.0^oC=273+55.0=328K

T_2 = final temperature of gas = 59.0^oC=273+59.0=332K

Now put all the given values in the above equation, we get:

\frac{0.892atm\times 6.35L}{328K}=\frac{1.05atm\times V_2}{332K}

V_2=5.46L

Thus, the final volume of gas will be, 5.46 L

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