Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that ![\mu = 32, \sigma = 1.5](https://tex.z-dn.net/?f=%5Cmu%20%3D%2032%2C%20%5Csigma%20%3D%201.5)
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus
![X - 32 = -1.645*1.5](https://tex.z-dn.net/?f=X%20-%2032%20%3D%20-1.645%2A1.5)
![X = 29.5](https://tex.z-dn.net/?f=X%20%3D%2029.5)
Heights of 29.5 and below could be a problem.
Answer:
A) Both estimates are slightly larger, so it is reasonable.
Step-by-step explanation:
Since 1/2 = 5/10
And 1/5 = 8/40
<u>Both estimates are larger</u>
Answer:
i think its 358
Step-by-step explanation:
Answer:
Step-by-step explanation:
![3xy-3x-2y+2\\(y-1)(3x-2)\\Check\\(y-1)(3x-2)\\Simplify\ and\ we\ get\ our\ question\\(y)(3x)+(y)(-2)+(-1)(3x)+(-1)(-2)\\3xy-2y-3x+2](https://tex.z-dn.net/?f=3xy-3x-2y%2B2%5C%5C%28y-1%29%283x-2%29%5C%5CCheck%5C%5C%28y-1%29%283x-2%29%5C%5CSimplify%5C%20and%5C%20we%5C%20get%5C%20our%5C%20question%5C%5C%28y%29%283x%29%2B%28y%29%28-2%29%2B%28-1%29%283x%29%2B%28-1%29%28-2%29%5C%5C3xy-2y-3x%2B2)
珠ɪᴢᴜᴍɪᴿᴬᴳᴱ
Your answer is 2,200 pupils.
If 990 is equal to 45% of the total amount of pupils, then to find 1% we can divide both 45 and 990 by 45.
990 ÷ 45 = 22, which is 1%, so then we multiply 22 by 100 to get 100% of the pupils, which gives us 2,200.
I hope this helps!