Answer:
Step-by-step explanation:
(x₁, y₁) = (19 , -4) & (x₂ ,y₂) = (17, -20)
![Slope =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=Slope%20%3D%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
![= \frac{-20-[-4]}{17-19}\\\\= \frac{-20+4}{17-19}\\\\= \frac{-16}{-2}\\\\= 8](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-20-%5B-4%5D%7D%7B17-19%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-20%2B4%7D%7B17-19%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-16%7D%7B-2%7D%5C%5C%5C%5C%3D%208)
m = 8
Parallel lines have same slope.
Parallel slope = 8
Slope of perpendicular line = ![\frac{-1}{m}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7Bm%7D)
Perpendicular slope = ![\frac{-1}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B8%7D)
Answer:
The correct answer is - 768.
Step-by-step explanation:
The given question is based on a specific pattern present in between the numbers in the given series -
Series = 25 50 99 196 388
to find - next number in series
let us find the relation between the initial two number:
25 - 50, here number 50 is two times of 25 or (x*2-0)
relation between 2nd and 3rd number:
50 - 99, here 99 is two times of 50 minus 1 or (x*2-1)
relation between 3rd and 4th number:
99 - 196, here 196 is two times of 99 minus 2 or (x*2-2)
relation between 4th and 5th number:
196 - 388, here 388 is the two times of 196 minus 4 or (x*2-4)
So on this pattern, the next number would be = x*2-8
388*2-8
= 768
what triangle you have a picture?
First you had to add by twenty-two from both sides of equation form.
![-22+4q+22>2+22](https://tex.z-dn.net/?f=-22%2B4q%2B22%3E2%2B22)
Then simplify by equation.
![4q>24](https://tex.z-dn.net/?f=4q%3E24)
Next, you divide by four from both sides of equation form.
![\frac{4q}{4}> \frac{24}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B4q%7D%7B4%7D%3E%20%5Cfrac%7B24%7D%7B4%7D)
Finally, simplify by equation.
![24/4=6](https://tex.z-dn.net/?f=24%2F4%3D6)
![24/6=4](https://tex.z-dn.net/?f=24%2F6%3D4)
![6*4=24](https://tex.z-dn.net/?f=6%2A4%3D24)
![4*6=24](https://tex.z-dn.net/?f=4%2A6%3D24)
![q>6](https://tex.z-dn.net/?f=q%3E6)
Final answer: ![\boxed{q>6}](https://tex.z-dn.net/?f=%5Cboxed%7Bq%3E6%7D)
Hope this helps!
And thank you for posting your question at here on brainly, and have a great day.
-Charlie
Answer:
z^0= 1
(2v+2)^0 = 1
3^0 = 1
0^0= 0
Step-by-step explanation:
When you raise (almost) anything to the power zero, you get 1 and when you raise 0 to any number except 0 is 0