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Sonbull [250]
3 years ago
15

The Escape speed at the surface of a certain planet is twice that of the earth. If the planet has radius twice of the Earth. wha

t is its mass in unit of earth's mass?​
Physics
1 answer:
gogolik [260]3 years ago
4 0

Answer:

1.32 × 1022 short tons

Explanation:

hope this helps

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An airplane crooses the United States from San Francisco to Boston in 4 hours 20 min. Find the average speed if the distance is
Anna007 [38]

Answer:

999.23 km/h

Explanation:

We can use the formula for average speed as "Distance divided time" to solve the problem.

Let's start by writing the time in hours: 4 h and 20 min is the same as 4 hours + 1/3 of an hour = 13/3 of an hour

Now we use this number in the quotient for average speed:

Average speed = 4330 km / (13/3) h = 12990 / 30  km/h = 999.23 km/h

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The weight of the windsurfer is 700 newtons. Calculate the moment exerted by the windsurfer on the sailboat ​
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3 years ago
Sirius A has a luminosity of 26 LSun and a surface temperature of about 9400 K.What is its radius?
wlad13 [49]

Answer

Given,

Sirius A surface temperature,T = 9400 K

Sirius A luminosity,L = 26 L₀

L₀ is the luminosity of sun.

Radius of sun =  695700000 m

Temperature on sun surface = 5780 K

Luminous intensity is given by:-

L=4 \pi R^{2} \sigma T^{4}

Now

\frac{L}{L_{0}}=\frac{4 \pi R^{2} \sigma T^{4}}{4 \pi R_{0}^{2} \sigma T_{0}^{4}}=26

\Rightarrow \frac{R^{2} T^{4}}{R_{0}^{2} T_{0}^{4}}=26

\Rightarrow R^{2}=26 \times \frac{R^{2} T_{0}^{4}}{T^{4}}=26 \times \frac{695700000^{2} \times 5780^{4}}{9400^{4}}

R=1341246640\ m=1.34 \times 10^{9}

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