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nlexa [21]
3 years ago
6

You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 240.0 kPa when the ther

mometer is in contact with boiling water. The boiling water is under regular atmospheric pressure. What is the temperature of the thermometer, when it reads a pressure of 431.0 kPa?
Physics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

396.97°C

Explanation:

Charles' Law explains that at constant volume, the pressure of an ideal gas is directly proportional to its temperature (in Kelvin).

P₁ ∝ T₁

P₁ = kT₁

k = constant of proportionality

(P₁/T₁) = (P₂/T₂)

P₁ = 240.0 kPa

T₁ = Boiling point of water = 100°C = 373.15 K

P₂ = 431.0 kPa

T₂ = ?

(240/373.15) = (431/T₂)

T₂ = (431 × 373.15) ÷ 240

T₂ = 670.12 K

T₂ = 396.97°C

Hope this Helps!!!

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Jobisdone [24]

Answer:

a. The speed is 2.39 m/s

b. The acceleration of the block is 10.2\frac{m}{s^{2} }

Explanation:

First, we have to do the energy balance where we consider two states, the first where the spring remains still and the second when it is stretched 0.400m:

K_{1} +U_{1}+W_{ext}=K_{2}+U_{2}\\K_{1}=0\\U_{1}=\frac{1}{2} kx^{2} _{1} =0\\W_{ext}=FΔx=(0.400m)\\

W_{ext}=20.4 Nm

U_{2} =\frac{1}{2} kx^{2} =\frac{1}{2} (76.0N/m)0.400^{2}=6.08Nm\\k_{2} =\frac{1}{2}mv^{2} _{2}  \\\frac{1}{2} mv^{2} _{2}=W_{ext}-U_{2}\\v_{2}=\sqrt{\frac{W_{ext}-U_{2}}{m} } \\v_{2}=\sqrt{\frac{20.4Nm-6.08Nm}{2.5kg} } \\v_{2}=2.39 \frac{m}{s}

To determine, the acceleration we solve the following equation for a:

F=ma\\a=\frac{F}{m} =\frac{51.0N}{5.00kg}\\a=10.2\frac{m}{s^{2} }

8 0
4 years ago
A 2-meter high wave with a wavelength of 100 meters and period of 20 seconds would be moving how fast?
hammer [34]
Velocity of wave= wavelength/wave period;
i.e., 100/20=5 meter/sec
8 0
3 years ago
True or False: If a point charge has electric field lines that point into it, the charge must be positive.
Licemer1 [7]

Answer:

False

Explanation:

If a point charge has electric field lines point into it,then charge must be negative because electric lines point into negative charges and point out of positive charges

8 0
3 years ago
How do amps correlate to brightness?
Nezavi [6.7K]
The watts determine the brightness. Watt is the unit of Power. And Power is equal to Voltage x Amps (current). So both the current and voltage determine the brightness.
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4 years ago
Two charges, Q1 and Q2, are separated by 6·cm. The repulsive force between them is 25·N. In each case below, find the force betw
Misha Larkins [42]

Answer:

a) 5 N b) 225 N c) 5 N

Explanation:

a) Per Coulomb's Law the repulsive force between 2 equal sign charges, is directly proportional to the product of the charges, and inversely proportional to the square of  the distance between them, acting along  the  line that joins the charges, as follows:

F₁₂ = K Q₁ Q₂ / r₁₂²

So, if we make Q1 = Q1/5, the net effect will be to reduce the force in the same factor, i.e. F₁₂ = 25 N / 5 = 5 N

b) If we reduce the distance, from r, to r/3, as the  factor is squared, the net effect will be to increase the force in a factor equal to 3² = 9.

So, we will have F₁₂ = 9. 25 N = 225 N

c) If we make Q2 = 5Q2, the force would be increased 5 times, but if at the same , we increase the distance 5 times, as the factor is squared, the net factor will be 5/25 = 1/5, so we will have:

F₁₂ = 25 N .1/5 = 5 N

3 0
3 years ago
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