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QveST [7]
3 years ago
12

How do prokaryotes differ from eukaryotic and how are they similar?

Physics
1 answer:
stealth61 [152]3 years ago
6 0
Prokaryotes = no nucleus; are usually more for simpler organisms
Eukaryotes = CARRY a nucleus
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When devising a model, scientists can only use the information available during their lifetime. This means that the current mode
11111nata11111 [884]

no, it not useless. we still learn Bohr's model in HS n dats almost 200 yr old! while there may be new models, previous one is good for explaining the basics. it is also useful to learn previous model n see how our understanding improves over time.


6 0
3 years ago
Read 2 more answers
A fish inside the water 12cm below the surface looking up through the water sees the outside world contained in a circular horiz
serg [7]

Answer:

13.6 cm

Explanation:

From Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

In the air, n₁ = 1, and light from the horizon forms a 90° angle with the vertical, so sin θ₁ = sin 90° = 1.

Given n₂ = 4/3:

1 = 4/3 sin θ

sin θ = 3/4

If x is the radius of the circle, then sin θ is:

sin θ = x / √(x² + 12²)

sin θ = x / √(x² + 144)

Substituting:

3/4 = x / √(x² + 144)

9/16 = x² / (x² + 144)

9/16 x² + 81 = x²

81 = 7/16 x²

x ≈ 13.6

4 0
4 years ago
Please help ASAP.
Bess [88]

Im not 100% sure you have to tell me if im wrong or not.

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3 0
3 years ago
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A hiker climbs a mountain. Starting at the base of the mountain, he first moved up 520m at a 32.0 degree angle. What is the fina
balu736 [363]

Answer:

\displaystyle \vec{d}=

Explanation:

<u>Displacement Vector</u>

Suppose an object is located at a position  

\displaystyle P_1(x_1,y_1)

and then moves at another position at

\displaystyle P_2(x_2,y_2)

The displacement vector is directed from the first to the second position and can be found as

\displaystyle \vec{d}=

If the position is given as magnitude-angle data ( z , α), we can compute its rectangular components as

\displaystyle x=z\ cos\alpha

\displaystyle y=z\ sin\alpha

The question describes the situation where the initial point is the base of the mountain, where both components are zero

\displaystyle P_1(0,0)

The final point is given as a 520 m distance and a 32-degree angle, so  

\displaystyle x_2=520\ cos32^o= 440.99\ m

\displaystyle y_2=520\ sin32^o=275.6\ m

The displacement is

\displaystyle \vec{d}=

5 0
3 years ago
6.Convert 22 °C to K. (°C = K - 273)
DIA [1.3K]

Answer:

295

Explanation:

if C = k - 273

k = C + 273

substitute 22 for C

K = 22 + 273

k = 295

3 0
3 years ago
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