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mojhsa [17]
4 years ago
13

What are the components of vector A if its magnitude is 70 m/s and makes an angle of 51.7° with the +x-axis?

Physics
1 answer:
storchak [24]4 years ago
3 0

Since, A is a vector. Hence, we can break it into two components (x and y)

Angle made by the velocity vector A with the x-axis = 51.7°

Magnitude of the vector A = 70 m/s

A_x = A \times Cos 51.7°

A_x = 70 \times 0.617

A_x = 43.4 m/s

A_y = 70 \times Sin 51.7°

A_y = 70 \times 0.784

A_y = 54.9 m/s

Hence, the option C is correct.

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Explanation:

d = Diameter of wheel = 27 cm

r = Radius = \frac{d}{2}=\frac{27}{2}=13.5\ cm

m = Mass of wheel = 800 g

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Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-245\times \frac{2\pi}{60}}{50}\\\Rightarrow \alpha=-0.51312\ rad/s^2

Moment of inertia is given by

M=\frac{1}{2}mr^2\\\Rightarrow M=\frac{1}{2}\times 0.8\times 0.135^2\\\Rightarrow M=0.00729\ kgm^2

Torque is given by

\tau=I\alpha\\\Rightarrow \tau=0.00729\times -0.51312\\\Rightarrow \tau=-0.0037406448\ Nm

The torque the friction exerts is -0.0037406448 Nm

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brainly.com/question/13936874

brainly.com/question/3406242

7 0
3 years ago
To drive a typical car at 40 mph on a level road for one hour requires about 3.2 × 107 J of energy. Suppose we tried to store th
tatiyna

Answer:

9000RPM

Explanation:

"Angular velocity" is directly related to kinetic energy, that is, the Kinetic energy equation would allow an approximation to the resolution investigated in the problem.

The equation for KE is given by:

KE = \frac{1}{2} lw ^ 2

Now, starting from there towards the <em>Angular equation of kinetic energy</em>, the moment of inertia (i) is used instead of mass (m), and angular velocity (w) instead of linear velocity (V)

That's how we get

KE_{Angular} = \frac{1}{2} Iw^2

calculating the inertia for a solid cylindrical disk, of

m = 400kg

r = 1.2 / 2 = 0.6m

I_{disk} = \frac{1}{2} mr^2 = (0.5) (400) (0.6)^2 = 72 kgm^2

We understand that the total kinetic energy is 3.2 * 10 ^ 7J, like this:

3.2*10^7 = \frac{1}{2} Iw^2 = (0.5) (72) w^2 = 36w^2w^2 = 3.2*10^7 / 36 = 0.0888*10^7 = 88.8*10^4

w = 9.43*10^2 = 943 rad / s

Thus,

943 rad / s ≈ 9000 rpm

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