So you need to put numbers before each compound to make sure there are the exact same number of elements on each side. If you put a 4 before NH4 there are 4 Nitrogen and now 16 hydrogen. I just played around with numbers and guessed until I got them even.
Hey there !
a) Pb(SO4)2 => <span> lead(II) sulfate
b) </span><span>The molar mass of this compound was calculated from the amount of atoms of each element, with its respective atomic masses
Pb = 207.2 a.m.u
S = 32.065 a.m.u
O = </span><span>15.9994 a.m.u
Therefore:
</span>Pb(SO4)2 = 207.2 + 32.065 * 2 + 15.9994 * 8 => <span>399.3252 g/mol
</span>
hope this helps!
Answer:
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Explanation:
This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.
<h3>Mass ratios:</h3>
In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:
Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:
Therefore, the results for NO₂ and N₂O₇ are 7.0:16.0 and 1.0:4.0 respectively
Learn more about atomic masses: brainly.com/question/5566317