Data:
M (Molar Mass) of C2H6
C = 2*12 = 24 amu
H = 6*1 = 6 amu
---------------------
MM C2H6 = 24+6 = 30 g/mol
P (pressure) = 1.6 atm
V (volume) = 12.7 L
<span>R = 0,082 atm .L/mol.K
n (</span>Number of mols) →
![n = \frac{m}{MM} m (mass) = ? T = 24ºC Celsius to Kelvin TK = TºC + 273 TK = 24 + 273 TK = 297 By the equation of state of the gases or equation of Clapeyron, we have: [tex]P*V = n*R*T](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Bm%7D%7BMM%7D%20m%20%28mass%29%20%3D%20%3F%20T%20%3D%2024%C2%BAC%20%20Celsius%20to%20Kelvin%20TK%20%3D%20T%C2%BAC%20%2B%20273%20TK%20%3D%2024%20%2B%20273%20TK%20%3D%20297%20%20%20%3Cspan%3EBy%20the%20equation%20of%20state%20of%20the%20gases%20or%20equation%20of%20Clapeyron%2C%20we%20have%3A%0A%20%20%20%3C%2Fspan%3E%5Btex%5DP%2AV%20%3D%20n%2AR%2AT%20)
<span>
Since </span>

<span>, we can perform the following substitution in the above Clapeyron equation:
</span>


multiply cross

Solving:




Answer:
25.03 grams of ethane gas
There are 0.1 moles of solute in 250 mL of 0.4 M solution.
Explanation:
First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.
250mL⋅
1L/1000mL⋅
0.4mol1L
Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.
I believe this would be Ba3P2 (the numbers are subscripts; meant to be little)
I am taking Honors Chem so I hope this helps!!
Answer:
Logs in a fire is an example of something burning, also changing its state of form. I think thats chemical change; going from wood to ashes. And charged batteries means they haven't been used yet or they were just charged, resulting in physical change.
Explanation:
I just learned this in science.
I hope this helps!