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Musya8 [376]
3 years ago
10

D5W is a solution used as an intervenous fluid.It is 5.0% by mass solution of the dextrose (C6H12O6) in water. if the density of

D5W is 1.029 g/ml. Calculate the molarity of the dextrose in the solution.
Chemistry
1 answer:
Alona [7]3 years ago
6 0

Answer:

0.29 mol/L

Explanation:

Its density is 1.029 g/ml so in a liter (1000 mL) there is 1029 g of solution, but only 5% is dextrose.

0.05x1029=51.45

So in a liter of D5W solution there is 51.45 g of dextrose.

Dextrose molar mass iss 180.156 g/mol, so in 51.45 g of dextrose there is

51.45/180.156=0.29 mol

In one liter of solution there is 0.29 mol of dextrose, so the molarity of such solution is 0.29 mol/L.

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Calculate the amount in moles and grams of KMnO4 present in 3dm^3 of 0.25M​
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Explanation:

Given data:

Number of moles of KMnO₄ = ?

Mass in gram = ?

Molarity of KMnO₄ = 0.25 M

Volume of KMnO₄ solution = 3 dm³ (3 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

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Molarity = number of moles  / L of solution

0.25 M = number of moles / 3 L

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