How large would the state of New York (235 miles across) be?

If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m

GaryK [48]

First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet

And the total number of snow flakes per minute on the entire lawn is:

(1350 snowflakes per minute per square foot) x (420 square feet) = 567,000 snowflakes per minute

In one hour (or 60 minutes) we get a total of:

(567,000 snowflakes per minute) x (60 minutes / 1 hour) = 34,020,000 snowflakes

The total mass of which would be:

34,020,000 snowflakes x 1.60 mg = 54,432,000 mg = 54.432 kg (as 1 kg = 1,000,000 mg).

So 54.432 kg of snow accumulates every hour on the lawn.

7 0

3 years ago

How does the circultatory system and muscular system work together?

grin007 [14]

Answer:

d.

Explanation:

i was think b at first but that doesnt really explain how it gets to the circulatory system so d because without the the regulation of the heart rate and oxgen rich blood the muscular system can do absolutely nothing

7 0

3 years ago

Hydroxylamine hydrochloride is a powerful reducing agent which is used as a polymerization catalyst. It contains 5.80 mass % H,

ludmilkaskok [199]

Answer: The empirical formula for the given compound is $H_{4}O_1N_1Cl_1=H_4NOCl$

Explanation:

We are given:

Percentage of H = 5.80 %

Percentage of O = 23.02 %

Percentage of N = 20.16 %

Percentage of Cl = 51.02 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 5.80 g

Mass of O = 23.02 g

Mass of N = 20.16 g

Mass of Cl = 51.02 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{5.80g}{1g/mole}=5.80moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{23.02g}{16g/mole}=1.44moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{20.16g}{14g/mole}=1.44moles$

Moles of Chlorine = $\frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{51.02g}{35.5g/mole}=1.44moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.44 moles.

For Hydrogen = $\frac{5.80}{1.44}=4.03\approx 4$

For Oxygen = $\frac{1.44}{1.44}=1$

For Nitrogen = $\frac{1.44}{1.44}=1$

For Chlorine = $\frac{1.44}{1.44}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : O : N : Cl = 4 : 1 : 1 : 1

Hence, the empirical formula for the given compound is $H_{4}O_1N_1Cl_1=H_4NOCl$

3 0

3 years ago

In a 1.0× 10–6 M solution of Ba(OH)2(aq) at 25 °C, identify the relative molar amounts of these species.

Marysya12 [62]

Thank you for posting your question here. Below is the solution:

HNO3 --> H+ + NO3-
HNO3 = strong acid so 100% dissociation 
** one doesn't need to find the molarity of water since it is the solvent 

0M HNO3 
1x10^-6M H3O+ 
1x10^-6M NO3- 
1x10^-8M OH-.....the Kw = 1x10^-14 = [H+][OH-] 
you have 1x10^-6M H+ so, 1x10^-14 / 1x10^-6 = 1x10^-8M OH- 

1x10^-6 Ba(OH)2 = strong base, 100% dissociation 
1x10^-6M Ba2+ 
2x10^-6M OH- since there are 2 OH- / 1 Ba2+ 
0M Ba(OH)2 
5x10^-9M H3O+

4 0

3 years ago

What is a tolerant of sea spray? I NEED HELP WITH THIS QUESTION !!! Answer fast for 20 poins

DedPeter [7]

Answer:

American Holly, Black Pine, Blue Pacific Juniper, Blue Dune Grass, Artemesia) MODERATELY SALT TOLERANT: plants always need protection from salt spray but will tolerate some inundations by storm surges. They are best used behind fences or buildings. (

3 0

3 years ago