Answer:
Explanation: The Holy Communion is a practice in Christianity, also recognised as one of the 7 sacraments (First Holy Communion). This is where a child (typically 7-10 years old) has their first Eucharist and confession. This is when they go to the priest and confess their sins, and can then claim the Eucharist, which is when they eat "the body of Christ". The small piece of bread given is known as "the body of Christ", and the wine as Jesus's blood. (....check next answer for the rest)
monicawiszowata avatar
After receiving the first Holy Communion, this is simply a natural procession in church. Priest will say "The Body of Christ", the receiver says "Amen", and eats the bread. Upon eating the bread, they do the sign of the cross. This is done to symbolise that Christ is among the receiver of the Communion.
Answer:
(1) reducing home prices—deflation; (2) reducing the rate at which the currency exchanges for other currencies—depreciation/devaluation.
Explanation:
hope it helps you and give me a brainliest
Maybe write the problem out or just watch tv
The reason why iron oxide has more mass than the iron is because Iron oxide has oxygen atoms, and pure iron does not.
When iron rusts and forms iron oxide, the iron oxide has more mass than the iron. Which statement correctly explains this
observation?
(A)Iron oxide has oxygen atoms, and pure iron does not.
(B)The oxygen atoms in iron oxide have more mass than the iron atoms in pure iron.
(C)The iron atoms in iron oxide have more mass than pure iron.
(D)There are more iron atoms in iron oxide than in pure iron.
When a chemical reaction takes place, other atoms are combined with pure elements to form compounds. This addition of another atom (oxygen) after reaction makes iron oxide formed heavier than pure iron.
Iron oxide is a chemical substance formed when pure iron rusts. The formation of iron oxide is a chemical reaction.
Hence, the correct answer to the question is; the iron is heavier because Iron oxide has oxygen atoms, and pure iron does not.
Learn more: brainly.com/question/6284546
The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g
<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>
1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g
<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>
Mass of H = 6H = 6 × 1 = 6 g
<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>
115 g of (NH₄)H₂PO₄ contains 6 g of H.
Therefore,
57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H
Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄
Learn more about mass composition:
brainly.com/question/13531044
