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Nadya [2.5K]
3 years ago
8

ASAP PLZ I WILL GIVE BRAINLIEST TO RIGHT ANSWER​

Mathematics
2 answers:
alexgriva [62]3 years ago
6 0

Answer:

15

Step-by-step explanation:

when its 2 negative they turn to a positive

Elina [12.6K]3 years ago
3 0

Answer:

9

Step-by-step explanation:

Absolute value means the distance the number is away from 0

-12 is 12 away from 0 and -3 is 3 away from 0

plug the new numbers into the equation to get

12 - 3 = 9

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last season a baseball player scored 14 runs in 18 games. this season the player scored 12 runs in 15 games. find the number of
bija089 [108]
Last season is 1.28 this season is 1.25
3 0
3 years ago
Solve the simultaneous equation<br> 2x+4y=1<br> 3x+5y=7b
Lyrx [107]

Step-by-step explanation:

  • 3x+5y=7b equation 1
  • 2x+4y=1

2x=-4y+1

  • x=(-4y+1)/2
  • x=(-4y+1)/2 in equation 1

3×(-4y+1)/2+5y=7b

(-12y+3)/2+5y=7b

(-12y+3+10y)/2=7b

(-12y+3)/2=7b

-12y+3=14b

-12y=14b-3

  • y=3-14b/12
  • y=3-14b/12 in x=(-4y+1)/2

x=(-4×{3-14b/12}+1)/2

x=(-3+14b)/3+1/2

x=14b/3×1/2

  • x=7b/3
8 0
3 years ago
Question 1
vivado [14]

Answer:

33, 792

Step-by-step explanation:

first convert the 8 miles to feet because our answers are in feet.

1 mile= 5280 feet

therefore 8 miles= 5280×8

= 42240

Dale and son covered 4/5 of the 42240 feet

= 4/5×42240

= 33,782 feet

4 0
2 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
What is 6/15-9/15 i need help plz
Xelga [282]

Answer:

-3/15 is the difference between 6/15-9/15

3 0
3 years ago
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