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2 years ago

Pls help need it ASAP :)

Mathematics

1 answer:

Elenna [48]2 years ago

6 0

Answer:

x = 4

y = 13

Step-by-step explanation:

x + y = 17

y = 2x + 5

substitute for y:

x + (2x + 5) = 17

reduce:

3x + 5 = 17

subtract 5 from each side:

3x = 12

divide both sides by 3:

x = 4

y = 2(4) + 5

y = 13

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1 year ago

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Let X = a laptop is selected and Y = a desktop is selected.

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Combination is used to determine the number of ways to select k objects from n distinct objects without replacement.

It is denotes as: ${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

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${8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70$

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

$P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\ =0.304832\\\approx0.305$

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

$P(Y\geq 3)=1-P(Y$

Thus, the probability that at least three of the selected computers are desktops is 0.401.

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