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I am Lyosha [343]
4 years ago
13

Identify an equation in slope – intercept‘s form for the line parallel to Y=5x+2 that passes through (-6,-1).

Mathematics
1 answer:
maksim [4K]4 years ago
8 0

Slope-intercept form of a line is y=mx+b where m= slope and b=y-intercept.

First step is to compare this line with the given line y=5x+2 to get the value of m.

After comparing we will get m=5.

Now slope of all parallel lines are equal which means if slope of this line is 5 then slope of the line which is parallel to this line will also be 5.

Point- slope form of a line is:

y-y_{1} =m(x-x_{1} )

Given the line passes through (-6,-1). So, plug in x1=-6, y1=-1 and m=5 in the above equation. So,

y-(-1)=5(x-(-6))

y+1=5(x+6)

y+1=5x+30

y=5x+30-1

y=5x+29.

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segment area = sector area - triangle DEF Area
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triangle DEF Area = (1/2) * 0.86603 * 400
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</span>
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Source:
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6 0
3 years ago
The infinite sequence 1, 6, 15, 28, 45, ... exhibits which pattern? multiply the term number by 2, subtract 1 from the result, m
Amanda [17]
The correct response is ;
<span>multiply the term number by 2, subtract 1 from the result, multiply by 2 times the term number, and divide the result by 2.
if term number is x,
the number in the pattern for xth term is ;
multiply term number by 2 - 2x
subtract 1 - 2x - 1
multiply by 2 times the term number - (2x-1) * 2x
divide by 2 - (</span>(2x-1) * 2x)/2
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second term x = 2
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third term x = 3
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fourth term  x= 4
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Therefore the above response shows the correct pattern
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4 years ago
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