Ask question

Ask question

All categories

2 years ago

5

Work is done when a person at rest holds a package vertically a. true b. false

1 answer:

Ksivusya [100]2 years ago

6 0

Answer:

False

Explanation:

Work= F*D and since the box isn't moving moved resulting in its displacement equalling 0, the work done on the package is 0.

You might be interested in

How does the constitution protect the rights of individuals against vivo

balandron [24]

The constitution protects the rights of people because in the constitution is the bill of rights. Which are admendments, which contain all or our rights.

8 0

2 years ago

The Work-Energy Principle states that work is equal to the

givi [52]

Answer:

the workenergy principle is measured in joules

8 0

2 years ago

A motorcycle has a mass of 2.50×10^2. A constant force is exerted on it for 60.0s. The motorcycles initial velocity is 6.00 m/s

Margarita [4]

The change in momentum is 5500 kg m/s

Explanation:

The change in momentum of an object is given by

$\Delta p = m(v-u)$

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have:

$m=2.50\cdot 10^2 kg$ (mass of the motorcycle)

$v=28.0 m/s$ (final velocity)

$u=6.0 m/s$ (initial velocity)

Therefore, the change in momentum is

$\Delta p=(2.50\cdot 10^2)(28.0-6.0)=5500 kg m/s$

Learn more about change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

8 0

3 years ago

Please answer the questions... I will surely mark you as the brainliest according to me :)

frutty [35]

Answer:

(a) You can tell that have the same strength because they have attracted the same amount of paper clips.

(b) Iron is used in electromagnets because steel retained magnetic properties after the power was turned off, but in the iron, the paper clips dropped off right away.

6 0

2 years ago

A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of

Rudiy27

Answer:

Explanation:

Given

mass of spring $m=100\ gm$

extension in spring $x=5\ cm$

downward velocity $v=70\ cm/s$

Position in undamped free vibration is given by

$u(t)=A\cos \omega _0t+B\sin \omega _0t$

where $\omega _0^2=\frac{k}{m}$

also $\frac{k}{m}=\frac{g}{L}$

$\omega _0^2=\frac{k}{m}=\frac{9.8}{0.05}$

$\omega _0=14$

$u(t)=A\cos(14t)+B\sin(14t)$

it is given

$u(0)=0$

$u'(0)=70\ cm/s$

substituting values we get

$A=0$

$u(t)=B\sin (14t)$

$u'(t)=14B\cos (14t)$

$70=14B$

$B=\frac{10}{2}$

$B=5$

$u(t)=5\sin (14t)$

3 0

3 years ago