d=? v=2.5 u=0 and t=5 therefore the formula to be used to find the distance my brother covered is d=1/2(v-u)t
d=1/2(2.5-0)5
=6.15m
Silver sable is in spiderman lol
Answer:
Explanation:
From the question we are told that:
Mass
Potential difference
Magnitude
Generally the equation for Velocity is mathematically given by
Generally the equation for Force is mathematically given by
Where
Therefore
First get the acceleration. Since it's uniform we use
Note the acceleration is negative since we start at a positive speed and end at zero.
Now the distance is the acceleration integrated twice. The first integral gives the velocity at any time, t
Notice if you put 5.5s for t in the expression we get 0 m/s as we should. Now to get the distance it traveled over this time we integrate this velocity expression:
So it travels 60.5 meters
To use standard enthalpies of formation to calculate the standard change in enthalpy for the melting of ice. kJ/mol
∆Hf° = standard heat of formation can be use to claculate the std enthalpy change as follows;
∆Hf°reaction = ∆Hf° p - ∆Hf° r
if the reaction is H₂O (s) ---- H₂O(l)
But
∆Hf°reaction = ∆Hf° H₂O(l) - ∆Hf° H₂O (s), which were -285kJ/mol and -291.8kJ/mol (obtained from the back of chemical process analysis text)
∆Hf°reaction = -285.8 kJ/mole - (-291.8 kJ/mole) = 6.0 kJ/mole = 6000 J/mole
heat gained by ice melting = heat lost by cooling water
(mass x ∆Hf°) ice = (mass x Cp x dT) liquid water
mass ice = (mass x Cp x dT) liquid water / (∆Hf°) ice
mass ice = 480 mL x 1.00 g/mL x 4.18 J/gC x (25-0 C) / 6000 J/mole
= 5.66 mole ice = 5.66 mole x 18.0 g /mole = 150 g of ice required to cool the 480mL of water.