1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svetoff [14.1K]
3 years ago
14

How to solve period per loop

Physics
1 answer:
erica [24]3 years ago
3 0

Answer:

f = 1 / T . f denotes frequency and T stands for the time it takes to complete one wave cycle measured in seconds. The SI frequency unit is Hertz (Hz), which equals 1/s (one cycle per second).

Explanation:

You might be interested in
yami pours powdered cocoa mix into milk and stirs it. then she microwaves the mixture for three minutes. when she takes the cup
MrRa [10]
Convection can best be observed as she blows the warm steam air that rises.

As the warm steam rises,  she forces displaces it with cool air from her mouth. Because the warm steam is less dense it rises and because the cool air is more dense, it displaces the warm air.

This scenario is an example of convection.
 
6 0
3 years ago
Read 2 more answers
If the half-life of a 2.0 gram sample of a radionuclide is 15 hours, then the half-life of a 1.0 gram sample of the same radionu
Lerok [7]

7.5 hours or 450 minutes. 15/2=7.5

5 0
3 years ago
If jim exerts a force of 2.0 N on a shopping cart, what force does the shopping cart exert on jim?
zloy xaker [14]
There are two possibilities for this question:
1- The shopping cart is at rest (not moving):
In this case:
∑Forces = 0
Force exerted by Jim + Force exerted by cart = 0
2 + Force exerted by cart = 0
Force exerted by cart = -2

2- The cart is moving as a result of a net force "m":
In this case:
∑Forces = m
Force exerted by Jim + Force exerted by cart = m
Force exerted by cart = m-2

5 0
4 years ago
A mass with a charge of 4.60 x 10-7 C rests on a frictionless surface. A compressed spring exerts a force on the mass on the lef
stira [4]

Answer:

The compression of the spring is 24.6 cm

Explanation:

magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C

magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C

distance between the two charges, r = 3 cm = 0.03 m

spring constant, k = 14 N/m

The attractive force between the two charges is calculated using Coulomb's law;

F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(4.6\times 10^{-7})(7.5\times 10^{-7})}{(0.03)^2} \\\\F= 3.45 \ N

The extension of the spring is calculated as follows;

F = kx

x = F/k

x = 3.45 / 14

x = 0.246 m

x = 24.6 cm

The compression of the spring is 24.6 cm

4 0
3 years ago
using newtons law a force of 250N is applied to an object that accelerates at a rate of 5M/s2 what is the mass of the object?
AURORKA [14]

Answer:

50 kg

Explanation:

F = ma

250 N = m (5 m/s²)

m = 50 kg

7 0
3 years ago
Other questions:
  • A spider hangs by a strand of silk at an eye level 20 cm in front of a plane mirror. You are behind the spider, 65 cm from the m
    11·1 answer
  • The “lead” in a lead pencil is actually made mostly of what form of carbon
    14·2 answers
  • We spend our lives in visible light without risks to our health. Yet exposure to UV waves in sunlight can cause skin cancer. Wha
    5·2 answers
  • Which statements describe an object in motion that has no external force acting on it? Check all that apply.
    7·2 answers
  • Sound is a mechanical wave; therefore, it __________.
    13·2 answers
  • A empty truck whose mass is
    6·1 answer
  • my friend wore a smart watch to bed,when he woke up in the morning it showed 300 steps taken how did this happen?
    7·1 answer
  • What do you know about velocity, acceleration and reference frame?
    15·1 answer
  • A compound microscope consist of an objective lens of focal length of 0.5cm and an eyepiece of focal length 1cm. The two lenses
    13·1 answer
  • When you apply a force, f, to an object you get an acceleration of 2m/s2. If you apply the same force to an object with twice th
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!