Ask question

Ask question

All categories

bogdanovich [222]

2 years ago

11

What would the Net Ionic Equation be for the following:

1 answer:

marin [14]2 years ago

3 0

The net equations are obtained from the double displacement of the cations and anions, then balance.

NH3(aq) + HC2H3O2 (aq) = NH4+(aq) + C2H3O2-(aq<span>)
</span><span>H+(aq) + C2H3O2-(aq) + NH3(aq) -> NH4+(aq) + C2H3O2-(aq)</span><span>

</span><span>2NaOH(aq) + H2SO4 (aq) = Na2SO4 (s)+ 2H2O (aq)
</span>H2S (aq) + Ba(OH)2 (aq) = BaS (s)+ 2H2O (aq)

You might be interested in

Hypochlorous acid decays in the presence of ultraviolet radiation. Assume that degradation occurs accord- ing to first-order kin

Dennis_Churaev [7]

Answer:

35.75 days

Explanation:

From the given information:

For first-order kinetics, the rate law can be expressed as:

$\mathsf{In \dfrac{C}{C_o} = -kt}$

Given that:

the rate degradation constant = 0.12 / day

current concentration C = 0.05 mg/L

initial concentration C₀ = 3.65 mg/L

$\mathsf{In( \dfrac{0.05}{3.65})= -(0.12) t}$

㏑(0.01369863014) = -(0.12) t

-4.29 = -(0.12)

t = -4.29/-0.12

t = 35.75 days

3 0

2 years ago

Please help meee 1st question

spayn [35]

360 seconds?

i’m guessing that is the answer as the question is unreasonable

5 0

2 years ago

A.it is physical change

PIT_PIT [208]

A physical change is when something don't permanently change

5 0

2 years ago

What is the density of air at 75 F and latm pressure? Express in lbm/ft3 and kg/m3

ser-zykov [4K]

Answer : The density of air in $lbm/ft^3$ and $kg/m^3$ is, $0.0743lbm/ft^3$ and $1.19kg/m^3$ respectively.

Explanation :

$PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}$

where,

P = pressure of air = 1 atm

V = volume of air

T = temperature of air = 297 K

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=(^oF-32)\times \frac{5}{9}$

$^oC=(75-32)\times \frac{5}{9}=24^oC$

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=273+^oC$

$K=273+24=297K$

n = number of moles

m = mass of air

M = average molar mass of air = 28.97 g/mole

$\rho$ = density of air = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the above formula, we get:

$\rho=\frac{PM}{RT}$

$\rho=\frac{(1atm)\times (28.97g/mole)}{(0.0821L.atm/mol.K)\times (297K)}$

$\rho=1.19g/L$

Now we have to calculate density in $lbm/ft^3$ .

Conversion used :

$1g/L=0.0624lbm/ft^3$

So,

$1.19g/L=\frac{1.19g/L}{1g/L}\times 0.0624lbm/ft^3=0.0743lbm/ft^3$

The density of air in $lbm/ft^3$ is, $0.0743lbm/ft^3$

Now we have to calculate density in $kg/m^3$ .

Conversion used :

$1g/L=1kg/m^3$

So,

$1.19g/L=1.19kg/m^3$

The density of air in $kg/m^3$ is, $1.19kg/m^3$

8 0

2 years ago

I’ve missed this question twice now. Please help

Molodets [167]

Answer:

then it only gotta be 2 other options .

Explanation:

4 0

2 years ago