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morpeh [17]
2 years ago
14

How are you doing? A. Good B. Bad C. Sad. D. Everything/nothing

Chemistry
2 answers:
vovangra [49]2 years ago
8 0
A.! Good Watching Eurovision
irinina [24]2 years ago
6 0
C.My cramps are killing me literally ;-;
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What is 140.2 in scientific notation
Akimi4 [234]

Answer:

1.402 * 10^2.

Explanation:

There are 3 digits before the decimal point so the exponent is 2.

4 0
3 years ago
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What is h2o? I’m in 1st grade
Crazy boy [7]

Answer:

Water

Explanation:

H20 means

H = Hydrogen

2 = 2 Hydrogen atoms

O = Oxygen (1 atom)

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2 years ago
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Carbon dioxide is released in________and taken in by plants in ______
alex41 [277]

Answer: A

Explanation:

Plants take in sunlight, water, carbon dioxide. The produce sugar (glucose) and other things. It could not be deforestation. It can't be evaporation, that is from the water cycle. It cant be C due to it talking about precipitation, which is also from the water cycle. Therefore, it can only be A

3 0
3 years ago
Please help...awarding brainliest if correct and lots of points.
abruzzese [7]

Silver chloride produced : = 46.149 g

Limiting reagent : CuCl2

Excess remains := 3.74 g

<h3>Further explanation</h3>

Reaction

silver nitrate + copper(II) chloride ⇒ silver chloride + copper(II) nitrate

Required

silver chloride produced

limiting reagent

excess remains

Solution

Balanced equation

2AgNO3 (aq) + CuCl2 (s) → 2AgCl(s) + Cu(NO3)2(aq)

mol AgNO3 :

= 58.5 : 169,87 g/mol

= 0.344

mol CuCl2 :

=21.7 : 134,45 g/mol

= 0.161

mol ratio : coefficient of AgNO3 : CuCl2 :

= 0.344/2 : 0.161/1

= 0.172 : 0.161

CuCl2  as a limiting reagent

mol AgCl :

= 2/1 x 0.161

= 0.322

Mass AgCl :

= 0.322 x 143,32 g/mol

= 46.149 g

mol remains(unreacted) for AgNO3 :

= 0.344-(2/1 x 0.161)

= 0.022

mass AgNO3 remains :

= 0.022 x 169,87 g/mol

= 3.74 g

8 0
2 years ago
Sodium<br> bromide+<br> Lithium<br><br> Based on Single replacement
Helga [31]

Answer:

the answer will be lithium bromide + sodium

Explanation:

because displace sodium from bromine there by liberating sodium as an element in the product side

6 0
3 years ago
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