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Alina [70]
2 years ago
5

Susan has 61/4 yards of yarn. She needs 3/4 of the yarn to make a mitten. How many yards of yarn does she need to make a mitten?

Mathematics
2 answers:
kompoz [17]2 years ago
6 0

Answer:

11 7/16 or 11.4375

Step-by-step explanation:

ivann1987 [24]2 years ago
3 0

Answer:

11.4375

Step-by-step explanation:

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When it comes to budgeting, which of the following is considered a fixed expense?
bogdanovich [222]
A fixed expense<span> is an </span>expense<span> that will be the same total amount regardless of changes in the amount of sales, production, or some other activity. A good example of this is rent or a mortgage.</span>
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Solve the following inequalities (picture attached)
11Alexandr11 [23.1K]
34.
(a) A. x < 4
(b) p > 1
(c) y <span>≤ 2.8

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6 0
2 years ago
How to solve - (12/h) -7f h=3 f=7
pogonyaev

Answer:

-53

Step-by-step explanation:

-(12/3)-7(7)

-4-49=-53

4 0
2 years ago
4.6 + 1.2x = 68.2 -1.8x I need help please and Thank you so much!
N76 [4]

Answer:

x = 21.2

Step-by-step explanation:

Mark me Brainliest?

7 0
2 years ago
Un boligrafo cuesta 30 ptas mas que un lapiz. Un muchacho ha comprado 8 boligrafos y 15 lapices. En total le han costado 700 pta
Firdavs [7]

Por un sistema de ecuaciones, tiene-se que:

  • Cada lapiz cuesta 20 ptas.
  • Cada boligrafo cuesta 50 ptas.

-------------------------

  • Considera-se un sistema de ecuaciones, con cada boligrafo custando x y cada lapiz custando y.
  • <u>Boligrafo cuesta 30 mas que un lapiz</u>, o sea, x = 30 + y
  • <u>8 boligrafos y 15 lapices cuesta 700</u>, o sea, 8x + 15y = 700

-------------------------

  • Aplicando el <u>primer ecuación en la segunda, </u>tiene-se el cuesto de cada lapiz:

8x + 15y = 700

8(30 + y) + 15y = 700

240 + 8y + 15y = 700

23y = 460

y = \frac{460}{23}

y = 20

Cada lapiz cuesta 20 ptas.

-------------------------

Por fin, el cuesto de cada boligrafo es dado por:

x = 30 + y = 30 + 20 = 50

Cada boligrafo cuesta 50 ptas.

Un problema similar es dado en brainly.com/question/24637096

4 0
2 years ago
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