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s344n2d4d5 [400]
4 years ago
6

1. How are systems of equations used in the real world? Help me plzzzz

Mathematics
1 answer:
nadezda [96]4 years ago
8 0

Answer:

Systems of linear equations are used in the real world by economists and entrepreneurs to find out when supply equals demand.It's all about the mullah, and if you don't know the numbers when you have a business, it might fail.

Step-by-step explanation:

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What is the value of x
bogdanovich [222]

Answer: 37

Step-by-step explanation:

74=2x

37=x

You are trying to get X by itself. Since it's 2x usually you would multiply it but in this case, divide it by itself into both sides so 74 divide 2 equals 37. If you know the order of operations then reverse it.

I'm just confused about how the answer choices are only 108 and 18.

8 0
2 years ago
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Which of the following points lies on the line 2x+3y=5?
mash [69]

Answer:

B(2,1). And C(-2,3)

Step-by-step explanation:

Tbh, you can just plug the numbers into the original equation :2x+3y=5

A.2x2+3x3=13 ≠5

B.2x2+3x1=5=5

C.-2x2+3x3=5=5

D.-2x2+3x0=-4≠5

So the answer is B and C lies on the line

6 0
2 years ago
14- 2.5f = 50 <br> Please help
nika2105 [10]

Answer:

<em>f=-14.4</em>

Step-by-step explanation:

14- 2.5f = 50\\\\14-50=2.5f\\\\-36=2.5f\\\\f=\frac{-36}{2.5}\\\\f=-14.4

7 0
2 years ago
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Which of the following is an arithmetic sequence?
dimulka [17.4K]

Answer:

1/2,-1/2,1/2,-1/2

Step-by-step explanation:

hope helpa

4 0
3 years ago
In a​ study, researchers wanted to measure the effect of alcohol on the hippocampal​ region, the portion of the brain responsibl
schepotkina [342]

Answer:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

Step-by-step explanation:

Information given

\bar X=8.19 cm^3 represent the sample mean

s=0.8 cm^3 represent the sample deviation

n=17 sample size  

\mu_o =9.02 represent the value to verify

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

System of hypothesis to check

We want to check if the true mean is less than the normal value of 9.02 cm^3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 9.02  

Alternative hypothesis:\mu < 9.02  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

6 0
3 years ago
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