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Minchanka [31]
4 years ago
9

The net of a cube is made up of five squares. true or false

Mathematics
1 answer:
salantis [7]4 years ago
6 0
The best answer would have to be false because a cube has six fases, and the net has the same number of fases in a square.
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Q=p(r+s) solve for p
Reil [10]
Q = p(r + s)
Use the distributive property
Q = pr + ps
Q = p x r + p x s
Q = p x p + r x s
Q = p^2 + rs
Subtract rs from both sides
Q - rs = p^2
Square root both sides
sqrt Q - rs = p
3 0
3 years ago
Read 2 more answers
The cost of taking your pet aboard the air flight with you in the continental US varies according to the airlines. The five numb
sergeinik [125]

Answer:

Lowest is 100

Highest is 125

Step-by-step explanation:

We use the 5 number summary to be the foundation of a graphical representation referred to as the box plot. One box would move from one quartile which is the lowest quartile Q1 to the another quartile Q3 which is the upper quartile.

Now if a box plot is to be made given the the information in this question, the box is going to go from Quartile 1 to Quartile 3.

Then the Lowest value would be 100 and the highest 125

3 0
3 years ago
Evaluate the function for the given input values f(x)=3x-1 find f(2) f(2)=
Harman [31]

Answer:

f(2) =5

Step-by-step explanation:

We have a function f(x) = 3x-1

When we find f(2) ,let x=2

f(2) = 3*2-1

      = 6-1

    =5

8 0
3 years ago
A rectangular garden has a width of five times an unknown variable x plus two. The length is one more than three times the same
wolverine [178]

Answer: just saying I’m pretty sure it’s 36... don’t put it cause I’m not 100% sure it’s right?

Step-by-step explanation:

5 0
3 years ago
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One parent is a cystic fibrosis carrier, and the other has
Marysya12 [62]

Answer:

A - 0%

B- 50%

C- 50%

D- 100%

Step-by-step explanation:

Cystic fibrosis is inherited in an autosomal recessive form, meaning that a person has to inherit two abnormal genes for the disease to manifest. In the case of this question, one parent is a gene carrier, so his genotype is Aa, while the other does not have the cystic fibrosis gene, so AA.

Performing the cross of Aa x AA, we can see that:

a.) The probability of a child would have cystic fibrosis is 0%, since the disease is recessive and to be affected it should receive a recessive gene from each parent.

b.) The probability of a child would be a carrier is 50%, as 50% of the crossing phenotypes are Aa.

c.) The probability of a child would not have cystic fibrosis and is not a carrier is 50%, as 50% of the child's genotype is AA.

d.) The probability of a child would be healthy is 100%, as of all possible phenotypes none is affected.

5 0
3 years ago
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