Question

In a field, dry fodder for the cattle is heaped in a

Answer 1

Answer:

volume of fodder=1/3pie R^2h=$\frac{1}{3} *\frac{22}{7} * (3.6)^2 *2.1=28.51m^3$

l^2=r^2+h^2

l^2=(2.1)^2+(3.6)^2

l^2=4.441+12.96=17.37

l=$\sqrt{17.37}$=4.17m

minimum area of polythene to cover fodder=pieRl=$\frac{22}{7} *3.6*4.17=47.18m^2$

the volume of fodder is $28.51m^3$ and minimum area of polythene to cover fodder in the  rainy seasonv47.18m^3